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anygoal [31]
2 years ago
13

You may have to recrystallize any or all of the components of your extraction mixture, benzoic acid, ethyl-4-aminobenzoate and f

luorenone, depending on their purity after isolation. You should have the recystallization solvents in your protocol. They are respectively:
Chemistry
1 answer:
hjlf2 years ago
6 0

Answer:

the Recrystallization solvents are;

-Sodium Hydroxide Base (NaOH)

- Hydrochloric Acid (HCl)

- Sand bath when acidic and basic components are removed.

Explanation:

Recrystallization is simply a technique used to purify an impure compound in a solvent.

Now, we want to purify the mixture of benzoic acid, Ethyl-4-aminobenzoate and fluorenone.

For the benzoic acid, it can be separated out of the mixture by addition of sodium hydroxide base (NaOH).

The Ethyl - 4 - aminobenzoate will be separated from the mixture by the addition of Hydrochloric Acid (HCl).

The fluorenone would be separated out by heating the mixture in a sand bath after the basic and acidic components have already been extracted out.

Thus, the Recrystallization solvents are;

-Sodium Hydroxide Base (NaOH)

- Hydrochloric Acid (HCl)

- Sand bath when acidic and basic components are removed.

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Calculate the molar solubility of PbBr2 (Ksp = 4.67x10-6) in 0.10M NaBr solution.
Softa [21]

Explanation:

PbBr_{2} will dissociate into ions as follows.

         PbBr_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Br^{-}(aq)

Hence, K_{sp} for this reaction will be as follows.

                   K_{sp} = [Pb^{2+}][Br^{-}]^{2}

We take x as the molar solubility of PbBr_{2} when we dissolve x moles of solution per liter.

Hence, ionic molarities in the saturated solution will be as follows.

               [Pb^{2+}] = [Pb^{2+}]_{o} + x

               [Br^{-}]^{2} = [Br^{-}]_{o} + 2x

So, equilibrium solubility expression will be as follows.

            K_{sp} = ([Pb^{2+}]_{o} + x)([Br^{-}]_{o} + 2x)^{2}

Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains [Br^{-}]_{o} = 0.10 and there will be no lead ions. So, [Pb^{2+}]_{o} = 0

So, [Br^{-}]_{o} + 2x will approximately equals to [Br^{-}]_{o}.

Hence, K_{sp} = x[Br^{-}]^{2}_{o}

            4.67 \times 10^{-6} = x \times (0.10)^{2}

                        x = 4.67 \times 10^{-4} M

Thus, we can conclude that molar solubility of PbBr_{2} is 4.67 \times 10^{-4} M.

5 0
3 years ago
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Answer:

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Explanation:

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Answer:

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How many atoms total are present in one molecule of 5-methyl-2 hexanol C7H16O
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Answer:

24 atoms

Explanation:

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