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Elis [28]
3 years ago
9

A garage door opener has a power rating of 350 watts. If the door is in operation for 30 seconds, how many joules of energy are

used? (Hint: Remember that 1 watt = 1 joule/sec)
Physics
1 answer:
Ksju [112]3 years ago
7 0
Because of the hint we can conclude what equation we need to solve this problem. We have power and duration that means that we need to express energy:

1 joule = 1watt * 1 second
or
E (energy) = P (power) * t (time duration)
E = 350 * 30 = 10500 joules.
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Encuentra la masa molar<br><br> TO<br><br> de 65 litros de SO2
shepuryov [24]

La masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

<h3>Masa molar</h3>

La masa molar de un compuesto depende de su masa presente en 1 mol, entonces:

                                          MM=\frac{m}{mol}

Para calcular la masa molar de un compuesto, simplemente suma las masas de cada elemento en el compuesto, así:

MM_O = 16g/mol\\MM_S= 32.1g/mol

                                32.1 + 2\times 16 = 64.1g/mol

Así, la masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

Obtenga más información sobre la masa molar en: brainly.com/question/17109809

8 0
3 years ago
Can a object have have zero velocity and nonzero acceleration?
vladimir1956 [14]

Answer:

yes

Explanation:

3 0
3 years ago
A 0.810 kg ball falls 2.5m. How much work does the force of gravity do on the ball?
lisabon 2012 [21]

Answer:

W = 19.845 J

Explanation:

Work is defined as W = Fdcos\theta, where F is the force exerted and d is the distance. Because the direction the ball is falling is the same direction as the force itself, \theta = 0 deg, and since cos(0) = 1, this equation is equivalent to W = Fd. In this case, the force exerted is the weight force, which is equivalent to m * g. Substituting you get:

W = mgd = 0.810 kg * 9.8 m/s^2 * 2.5m

W = 19.845 J

6 0
3 years ago
Everyone is trying to living a perfect life via social media.
Stells [14]

Answer:

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is this a question?

Explanation:

7 0
3 years ago
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a d
Mnenie [13.5K]

Answer:

(C) 40m/s

Explanation:

Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's  velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

6 0
3 years ago
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