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Elis [28]
2 years ago
9

A garage door opener has a power rating of 350 watts. If the door is in operation for 30 seconds, how many joules of energy are

used? (Hint: Remember that 1 watt = 1 joule/sec)
Physics
1 answer:
Ksju [112]2 years ago
7 0
Because of the hint we can conclude what equation we need to solve this problem. We have power and duration that means that we need to express energy:

1 joule = 1watt * 1 second
or
E (energy) = P (power) * t (time duration)
E = 350 * 30 = 10500 joules.
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3 years ago
A garage door opener has a power rating of 350 watts.
Lelechka [254]
We Know, Power = Energy/Time
Substitute the known value. which is P = 350 watt, & T = 30 sec
350 = E/30 
E = 350 * 30
E = 1050 Joules.

So, your answer is 1050 Joules.
Hope this helps! Keep studying! 
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