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3 years ago

A. What is an atom's electron configuration?

Chemistry

2 answers:

Tju [1.3M]3 years ago

5 0

Answer:

It is the distributions of electron on the three levels

Explanation:

The three levels are : K . L . M . N

yaroslaw [1]3 years ago

5 0

Electron configuration is the amount of electrons in each shell and how many shells so say like if the atomic number was 15 the max in first shell is 2 then 2nd is 8 and there is 5 left. So it would e 2,8,5

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3 years ago

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3 years ago

Read 2 more answers

Fe2O3(s) 2Al(s)Al2O3(s) 2Fe(s) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.73

son4ous [18]

Answer:

$\Delta S=54.3\frac{J}{K}$

Explanation:

Hello!

In this case, for the given reaction, we can write the equation to compute the entropy change as shown below:

$\Delta s=2\Delta S_{Fe}+\Delta S_{Al_2O_3}-2\Delta S_{Al}-\Delta S_{Fe_2O_3}$

Letting:

$\Delta s_{Fe}=27.3\frac{J}{mol*K}\\\\ \Delta s_{Fe_2O_3}=84.4\frac{J}{mol*K}\\\\\Delta s_{Al}=28.3\frac{J}{mol*K}\\\\\Delta s_{Al_2O_3}=51.00\frac{J}{mol*K}$

We obtain the entropy change per mole of Fe2O3(s): $\Delta s=2*27.3\frac{J}{mol*K}+84.4\frac{J}{mol*K}-2*28.3\frac{J}{mol*K}-51.0\frac{J}{mol*K} \\\\\Delta s=31.4\frac{J}{mol*K}$

Finally, the total entropy change when 1.73 moles of Fe2O3(s) react turns out:

$\Delta s=31.4\frac{J}{mol*K}*1.73mol\\\\\Delta S=54.3\frac{J}{K}$

Best regards!

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3 years ago