Question

What is the total amount of work required to

Answer 1

Answer:

$W = 1.6 \times 10^{-17} J$

Explanation:

Work done to move a charge through a given potential difference is

$W = q(\Delta V)$

here

q = magnitude of charge

$\Delta V$ = potential difference

here it is given that charge of the particle is same as charge of proton

$q = 1.6 \times 10^{-19} C$

$\Delta V = 100 V$

now we have

$W = (1.6 \times 10^{-19}) (100)$

$W = 1.6 \times 10^{-17} J$