How much heat is absorbed by 15.5g of water when it's temperature is increased from 20.0C the specific heat of the water is 4.18
1 answer:
Hello!
The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for Heat Transfer, in the following way (assuming that the heat increase is 20°C):
So, the Heat absorbed by water is 1297,04 J
Have a nice day!
The exercise doesn't say the final temperature, but we are going to assume that the increase is of 20 °C (The procedure is the same, just change the final temperature) To calculate the heat absorbed by water, we need to use the equation for Heat Transfer, in the following way (assuming that the heat increase is 20°C):
So, the Heat absorbed by water is 1297,04 J
Have a nice day!
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Answer:
60.42% is the percent yield of the reaction.
Explanation:
Moles of methane gas at 734 Torr and a temperature of 25 °C.
Volume of methane gas = V = 26.0 L
Pressure of the methane gas = P = 734 Torr = 0.9542 atm
Temperature of the methane gas = T = 25 °C = 298.15 K
Moles of methane gas = n
Moles of water vapors at 700 Torr and a temperature of 125 °C.
Volume of water vapor = V' = 23.0 L
Pressure of water vapor = P' = 700 Torr = 0.9100 atm
Temperature of water vapor = T' = 125 °C = 398.15 K
Moles of water vapor gas = n'
According to reaction , 1 mol of methane reacts with 1 mol of water vapor. As we can see that moles of water vapors are in lessor amount which means it is a limiting reagent and formation of hydrogen gas will depend upon moles of water vapors.
According to reaction 1 mol of water vapor gives 3 moles of hydrogen gas.
Then 0.6402 moles of water vapor will give:
of hydrogen gas
Moles of hydrogen gas obtained theoretically = 1.9208 mol
The reaction produces 26.0 L of hydrogen gas measured at STP.
At STP, 1 mole of gas occupies 22.4 L of volume.
Then 26 L of volume of gas will be occupied by:
Moles of hydrogen gas obtained experimentally = 1.1607 mol
Percentage yield of hydrogen gas of the reaction:
60.42% is the percent yield of the reaction.