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sammy [17]
4 years ago
7

I throw a ball upward at 40 m/s what is the acceleration

Physics
1 answer:
Angelina_Jolie [31]4 years ago
6 0
You'll need to use the formula <span><span><span>v2f</span>=<span>v2o</span>+2aΔs</span><span><span>vf2</span>=<span>vo2</span>+2aΔs</span></span><span>, where </span><span><span>v2f</span><span>vf2</span></span><span> is final velocity squared, </span><span><span>v2o</span><span>vo2</span></span><span> is initial velocity squared, a is acceleration (equal to g), and </span><span><span>Δs</span><span>Δs</span></span><span> is displacement. 

Hope this helps. </span>
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Marisa does 3.2J of work to lower the window shade in
Pani-rosa [81]

Work is considered as the Force performed on a body to move it a certain distance, that is

W = Fd

Here

W = Work

F = Force

d = Distance

In this case we have the values of work and distance, therefore clearing for the Force we would have to

F = \frac{W}{d}

Replacing,

F = \frac{3.2J}{8m}

F = 0.4N

Therefore the force that Marissa must exert on the windows shade is 0.4N

5 0
3 years ago
A potential difference of 300 volts is applied to a 2.0-µf capacitor and an 8.0-µf capacitor connected in series. (a) What are t
zubka84 [21]

Answer:

a) Q1=Q2=480μC   V1=240V   V2=60V

b) Q1=96μC   Q2=384μC   V1=V2=48V

c) Q1=Q2=0C    V1=V2=0V

Explanation:

Let C1 = 2μC  and  C2=8μC

For part (a) of this problem, we know that charge in a series circuit, is the same in C1 and C2. Having this in mind, we can calculate equivalent capacitance first:

C=\frac{1}{\frac{1}{C1} +\frac{1}{C2} } = 1.6\mu C

Q_{T} = V_{T}*C_{T} = 480\mu C

V1 = \frac{Q1}{C1}=240V

V2 = \frac{Q2}{C2}=60V

For part (b), the capacitors are in parallel now. In this condition, the voltage is the same for both capacitors:

V1=V2   So,  \frac{Q1}{C1} = \frac{Q2}{C2}

Total charge is the same calculated for part (a), so:

\frac{Qt - Q2}{C1} = \frac{Q2}{C2}   Solving for Q2:

Q2 = 384μC    Q1 = 96μC.

Therefore:

V1=V2=48V

For part (c), both capacitors would discharge, since their total voltage of 300V would by applied to a wire (R=0Ω). There would flow a huge amount of current for a short period of time, and capacitors would be completely discharged. Q1=Q2=0C  V1=V2=0V

3 0
3 years ago
The electric potential in a region of uniform electric field is -1600 V at x = -1.30 m and + 2000 V at x =+ 1.80 m . What is Ex?
Inga [223]

Answer:

-1161.29 V/m

Explanation:

The x component of electric field will be given by

E_x= -\frac {\triangle V}{\triangle x}

Here \triangle V is the change in voltage while triangle x is the change in x

E_x= -\frac {+2000 V--1600V}{\triangle 1.8--1.3}=-\frac {3600}{3.1}=-1161.29 V/m

6 0
3 years ago
Sun is not a planet.why?.​
VARVARA [1.3K]

Answer:

Because it is a star.

Explanation:

7 0
3 years ago
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How many meters are in 7.80 light years. 3 sig figs
Helga [31]

Answer:

<h2>16 meters are in 7.80 light years </h2>

Explanation:

7.80ly=7.379370e+16m

6 0
1 year ago
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