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sammy [17]
3 years ago
7

I throw a ball upward at 40 m/s what is the acceleration

Physics
1 answer:
Angelina_Jolie [31]3 years ago
6 0
You'll need to use the formula <span><span><span>v2f</span>=<span>v2o</span>+2aΔs</span><span><span>vf2</span>=<span>vo2</span>+2aΔs</span></span><span>, where </span><span><span>v2f</span><span>vf2</span></span><span> is final velocity squared, </span><span><span>v2o</span><span>vo2</span></span><span> is initial velocity squared, a is acceleration (equal to g), and </span><span><span>Δs</span><span>Δs</span></span><span> is displacement. 

Hope this helps. </span>
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A magnetic field is entering into a coil of wire with radius of 2(mm) and 200 turns. The direction of magnetic field makes an an
frozen [14]

Answer:

a) <em>2.278 x 10^-5 volts</em>

b) <em>1.139 x 10^-6 Ampere</em>

c) <em>2.59 x 10^-11 W</em>

Explanation:

The radius of the wire r = 2 mm = 0.002 m

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direction of the magnetic field ∅ = 25°

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varying time = 2 sec

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==> A = 3.142 x 0.002^{2} = 1.257 x 10^-5 m^2

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==> Φ = 2.278 x 10^-7 Wb

The induced EMF is given as

E = NdΦ/dt

where dΦ/dt = (2.278 x 10^-7)/2 = 1.139 x 10^-7

E = 200 x 1.139 x 10^-7 = <em>2.278 x 10^-5 volts</em>

<em></em>

<em></em>

b) If the two ends are connected to a resistor of 20 Ω, the current through the resistor is given as

I = E/R

where R is the resistor

I = (2.278 x 10^-5)/20 = <em>1.139 x 10^-6 Ampere</em>

<em></em>

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<em> </em>c) power delivered to the resistor is given as

P = IE

P = (1.139 x 10^-6) x (2.278 x 10^-5) = <em>2.59 x 10^-11 W</em>

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