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anygoal [31]
3 years ago
5

You obtain a 100-W light bulb and a 50-W light bulb. Instead of connecting them in the normal way, you devise a circuit that pla

ces them in series across normal household voltage. Which statement is correct? a. Both bulbs glow at the same reduced brightness. b Both bulbs glow at the tame increased brightness c. The 100-W bulb glows more brightly than the 50-W bulb d. The 50-W bulb glows more brightly than the 100-W bulb
Physics
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

The 50-W bulb glows more brightly than the 100-W bulb

Explanation:

The bulb has a rating of 100 W under 110 V . So it will glow with full brightness when it is fed 110 V . When bulbs are in parallel combination , each bulb receives 110 V . So they glow with full brightness .

When they are in series combination , 110 supply voltage gets distributed between the , thus  , reducing the voltage appearing on each of them less than 110 V . So their brightness is reduced.

resistance = V

Bulb having high wattage rating has low resistance resulting in higher current . In the second case , both have same current as they are in series combination . So more heat will be generated in bulb having more resistance . Since 50 W bulb has higher resistance , it will glow brighter than 100 W bulb.

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Answer:

Explanation:

a ) Between r = 0 and r = r₁

Electric field will be zero . It is so because no charge lies in between r = 0 and r = r₁ .

b ) From r = r₁ to r = r₂

At distance r , charge contained in the sphere of radius r

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c )

Outside of r = r₂

charge contained in the sphere of radius r = Q

Applying Gauss's law

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4πr² E = Q  / ε₀

E = Q  / 4πε₀r²

E ∝ 1 / r² .

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4 0
3 years ago
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Someone help please by providing work and answers please :)
Nastasia [14]
First we gotta use an equation of motion:

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Our vertical distance d= 100 m, initial vertical speed u = 0 m/s (because velocity is fully horizontal), and vertical acceleration a = 9.8 m/s2 because of gravity. Let's plug it all in!

100 = 0 + \frac{1}{2} (9.8) {t}^{2}

Now we just need to solve for t:

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Hit the calculators, and you'll get 4.5 seconds!
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