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vlabodo [156]
4 years ago
7

A 230.0 kg bear grasping a vertical tree slides down at constant velocity. What is the friction force between the tree and the b

ear?
Physics
2 answers:
vovangra [49]4 years ago
8 0
Well, it's equal to the weight of the bear, which is 230*10=2300 N
dezoksy [38]4 years ago
8 0
Hi there! Thanks for asking here on Brainly. <span>✉
</span>
Solving the dynamic equilibrium: 

<span>Friction = Gravity = ma
(230.0 kg)*(10 m/s2) =
23000 N

So the friction force between the tree and bear is 2300 N.

</span><span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia </span></span>
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Answer:

negative acceleration of 4m/s²

Explanation:

Given parameters:

Initial velocity  = 66m/s

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Unknown:

Description of the acceleration  = ?

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Acceleration is the rate of change of velocity with time.

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3 years ago
two masses are kept 2 metre apart there is gravitational force of 2 Newton what is the gravitational force when they are kept at
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Explanation:

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Inputting values into the formula :

2 = Gm1m2 / 2^2 - - - - - (1)

At a distance 'r' of 4meters apart:

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Inputting values

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