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vodomira [7]
3 years ago
11

A piano tuner strikes a tuning fork at the same time he strikes a piano key with a note of a similar pitch. If he hears 3 beats

per second, and the tuning fork produces a standard 440 Hz tone. Then what was the frequency produced by the struck piano string?
Physics
1 answer:
jeyben [28]3 years ago
3 0
F1-f2 = 3 beats per second = 3 Hz (since 1 beat/second = 60 beats/minute = 1 Hz).

Where, f1 = frequency of tuning fork, f2 = frequency produced by the piano.

Therefore,
f2 = f1 - 3 = 440 -3 = 437 Hz
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A 16.0 kg child on roller skates, initially at rest, rolls 2.0 m down an incline at an angle of 20.0° with the horizontal. If th
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RC time constant circuit if R 50 KOC-21 a TOSS c. 1.05 s . what is the expected RC value b. 10.55 d. 0.105 s
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Time constant of RC circuit is 0.105 seconds.

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Capacitance, C=2.1\ \mu F=2.1\times 10^{-6}\ F

We need to find the expected time constant for this RC circuit. It can be calculated as :

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\tau=5\times 10^4\times 2.1\times 10^{-6}

\tau=0.105\ s

So, the time constant for this RC circuit is 0.105 seconds. Hence, this is the required solution.

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3 years ago
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