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2 years ago

If you average 22.8 meters/min, how many seconds will it take you to travel 467 m?

Physics

2 answers:

Agata [3.3K]2 years ago

6 0

Speed = 22.8m/min
= 22.8 / 60
=0.38m/s

time = distance/ speed
= 467/0.38
= 1252.63s

n200080 [17]2 years ago

4 0

I solved the question for you on the picture below. It's a simple conversion problem that I have solved using traditional classroom methods. If you have any questions please comment on my answer.

Hope this helps!

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An experiment is designed to investigate the relation between the pressure and temperature in a tank that has a constant volume

viva [34]

Answer:

3rd order polynomial

Explanation:

Given that the increase in the order of the polynomial the error between the curve fit and measured data will decreases hence :

The polynomial order that is best to use is the 3rd order polynomial, this is because using a 3rd order polynomial will produce a less variance and a low Bias

4 0

2 years ago

The escape velocity of any object from Earth is 11.2 km/s. (a) Express this speed in m/s and km/h. (b) At what temperature would

natima [27]

Answer:

a ) 11.1 *10^3 m/s = 39.96 Km/h

b) T_{o2} =1.58*10^5 K

Explanation:

a) $v_{es} =v_{rms}$ = 11.1 km/s =11.1 *10^3 m/s = 39.96 Km/h

M_O2 = 32.00 g/mol =32.0*10^{-3} kg/mol

gas constant R = 8.31 j/mol.K

$v_{rms} = \sqrt{ \frac{3RT}{M}}$

So, $v_{rms,o2} =\sqrt{ \frac{3RT_{o2}}{M_{o2}}}$

multiply each side by M_{o2}, so we have

$v_{rms,o2}^2 *M_{o2} =3RT_{o2}$

solving for temperature T_{o2}

$T_{o2} = \frac{v_{rms,o2}^2 *M_{o2}}{3R}$

In the question given, $v_{rms} =v_{es}$

$T_{o2} = \frac{(11.1*10^3)^2 *32.0*10^{-3}}{3*8.31}$

T_{o2} =1.58*10^5 K

7 0

3 years ago

Two spaceships are observed from earth to be approaching each other along a straight line. Ship A moves at 0.40c relative to the

nirvana33 [79]

Answer:

0.80 c

Explanation:

The computation of speed is shown below:-

Here, The speed of the captain ship A report for speed of the ship B which is

$S = \frac{S_A + S_B}{1 + \frac{(S_AS_B)}{c^2} }$

where

$S_A$ indicates the speed of the ship A

$S_B$ indicates the speed of the ship B

and

C indicates the velocity of life

now we will Substitute 0.40c for A and 0.60 for B in the equation which is

$S = \frac{0.40c + 0.60c}{1 + \frac{(0.40c)(0.60c)}{c^2} }$

after solving the above equation we will get

0.80 c

So, The correct answer is 0.80c

5 0

2 years ago

Do the data for the first part of the experiment support or

mrs_skeptik [129]

Answer:

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7 0

2 years ago

Which best compares freezing and condensation?

bearhunter [10]

Condensation is a change of state from vapour to liquid while freezing is also a change of state, from liquid to solid. Both are change of states.

Additionally, condensation requires much more energy to change the state of vapor to liquid than it does it change the state of liquid to solid.

4 0

2 years ago

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