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Scilla [17]
2 years ago
7

If you average 22.8 meters/min, how many seconds will it take you to travel 467 m?

Physics
2 answers:
Agata [3.3K]2 years ago
6 0
Speed = 22.8m/min
= 22.8 / 60
=0.38m/s

time = distance/ speed
= 467/0.38
= 1252.63s
n200080 [17]2 years ago
4 0
I solved the question for you on the picture below. It's a simple conversion problem that I have solved using traditional classroom methods. If you have any questions please comment on my answer.

Hope this helps!

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Ken’s prediction for December was –5°C.
Veronika [31]

Answer:

-2 degrees

Explanation:

just subtract

5 0
3 years ago
Read 2 more answers
The average energy per unit time per unit area that reaches the upper atmosphere of the Earth from the Sun, called the solar con
Lynna [10]

Answer: 5.34 MJ

Explanation: The window is a rectangle with area:

A = 1.1(1.5)

A = 1.65 m²

We know that only 0.9 kW/m² reaches Earth so:

P = 0.9\frac{kW}{m^{2}}(1.65)m^{2}

P = 1.485 x 10³ W

Watts is an unit of Power and it can also be written as J/s.

An hour has 3600s or 3.6 x 10³s, so:

E = 1.485 x 10³ \frac{J}{s}(3.6 x 10³s)

E = 5.346 x 10⁶ J

Mega is equal to 10⁶, then:

E = 5.35 MJ

A 1.1 m by 1.5 m window collects, during 1 hour of daylight, 5.35 MJ

8 0
3 years ago
Two small objects each with a net charge of Q (positive) exert a force of magnitude F on each other. We replace one of the objec
erik [133]

Answer:

option B

Explanation:

we know,

Force between two charge is calculated by

F = \dfrac{kq_1q_2}{r^2}

r is the distance between the two charges

k is Coulomb constant.

give two small object with charge Q

now, Force

F = \dfrac{kQQ}{r^2}......(1)

now,

New force if another charge is equal to 4 Q

F' = \dfrac{kQ(4Q)}{r^2}

F' = 4\dfrac{kQQ}{r^2}

now from equation 1

F' = 4 F

Hence, the correct answer is option B

5 0
3 years ago
4. A steel cable spanning a river is 220.000 m long when the temperature is 30.°C.
romanna [79]

Answer:

219.9208  m

Explanation:

The new length is given by

New length= Original length *(1-Temperature change*coefficient of

thermal expansion of steel)

Here, the change in temperature is 30^{\circ}-0^{\circ}= 30^{\circ}

New length= 220.000(1-30*12x10^{-6}=219.9208m

Therefore, the new length will be 219.9208 m

5 0
3 years ago
Calculate the frequency of the wave shown below.
jenyasd209 [6]

\color{skyblue}{ \underline{  \frak { \: option \: ( \: c \: )  =  2 \: hertz   ✓}}}

\:  \:

Given :

  • Wavelength ( λ ) = 2 m

\:  \:

  • Speed = 4 m/s

\:  \:

We, have to find frequency :

\:

  • \large \tt \: Frequency =  \frac{Speed}{Wavelength ( \: λ \: )}

\:  \:

  • \large \tt \: Frequency =  \frac{4}{2}

\:  \:

  • \large \tt \: Frequency = \cancel  \frac{4}{2}

\:  \:

  • \pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}

\:  \:

Hope Helps!

5 0
2 years ago
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