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3 years ago

A person who is interested in the brain and its functions might pursue a career in

Chemistry

2 answers:

Radda [10]3 years ago

5 0

C neuroscience is your answer.

dedylja [7]3 years ago

4 0

Answer:

Explanat C nutro sience srry i f i did not help

You might be interested in

How many moles of carbon (C) atoms are equivalent to 38.1 g C?

Alla [95]

To convert grams to moles, we need the molar mass of carbon. this can be founded in the periodic table.

molar mass of C= 12.0 g/mol

38.1 g C (1 mol C/ 12.0 grams)= 3.18 moles of C

4 0

4 years ago

Calculate the freezing point of a solution 1.25 g benzene (C6H6) in 125 g of chloroform (CHCl3).

posledela

Answer:

The freezing point for the solution is -64.09°C

Explanation:

This problem can be solved, by the freezing point depression. This colligative problem shows, that the freezing point of a solution is lower than the freezing point of pure solvent.

ΔT = Kf. m

ΔT = T° freezing pure solvent - T° freezing solution

Kf = Cryscopic constant, for chloroform is 4.68

T°freezing pure solvent = -63.5°C

m is mol/kg of solvent → molality

Let's determine the moles of benzene

1.25 g / 78 g/mol = 0.0160 mol

Let's convert the mass of solvent to kg

125 g . 1kg / 1000 g = 0.125 kg

m = 0.0160 mol / 0.125 kg → 0.128 m

Let's go to the formula to replace the data

-63.5°C - T° freezing solution = 4.68 °C/m . 0.128 m

T° freezing solution = - (4.68 °C/m . 0.128 m + 63.5°C)

T° freezing solution = - 64.09°C

3 0

3 years ago

A student analyzed an unknown sample that contained a single anion. The sample gave a yellow precipitated upon addition of a sol

kenny6666 [7]

<h3>Answer:</h3>

Anion present- Iodide ion (I⁻)

Net ionic equation- Ag⁺(aq) + I⁻(aq) → AgI(s)

<h3>Explanation:</h3>

In order to answer the question, we need to have an understanding of insoluble salts or precipitates formed by silver metal.

Additionally we need to know the color of the precipitates.

Some of insoluble salts of silver and their color include;

Silver chloride (AgCl) - white color
Silver bromide (AgBr)- Pale cream color
Silver Iodide (AgI) - Yellow color
Silver hydroxide (Ag(OH)- Brown color

With that information we can identify the precipitate of silver formed and identify the anion present in the sample.

The color of the precipitate formed upon addition of AgNO₃ is yellow, this means the precipitate formed was AgI.
Therefore, the anion that was present in the sample was iodide ion (I⁻).
Thus, the corresponding net ionic equation will be;

Ag⁺(aq) + I⁻(aq) → AgI(s)

4 0

3 years ago

The half-life for the radioactive decay of calcium-47 is 4.5 days. how many half-lives have elapsed after 27 days?

Evgesh-ka [11]

1 half-life - 4.5 days
x half-lives - 27 days

x=(1*27)/4.5=6
6 <span>half-lives have elapsed after 27 days.</span>

8 0

4 years ago

Read 2 more answers

Classical bonding in NaH2PO4

lesantik [10]

$NaH_2PO_4$ , a crystal structure with a short symmetrical hydrogen bond.

<h3>What is Classical bonding?</h3>

Classical models of the chemical bond. By classical, we mean models that do not take into account the quantum behaviour of small particles, notably the electron. These models generally assume that electrons and ions behave as point charges which attract and repel according to the laws of electrostatics.

Sodium dihydrogen phosphate is a derivative composed of glycerol derivatives formed by reacting mono and diglycerides that are derived from edible sources with phosphorus pentoxide followed by neutralization with sodium carbonate.

Bonding in $NaH_2PO_4$

$NaH_2PO_4$ , a crystal structure with a short symmetrical hydrogen bond. Sodium dihydrogen phosphate ( $NaH_2PO_4$ ) is monoclinic, space group P2,/c, with a= 6.808 (2), b= 13.491 (3), c=7.331 (2)/~, fl=92.88 (3) ; Z=8.

Learn more about the bond here:

brainly.com/question/10777799

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7 0

2 years ago