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schepotkina [342]
3 years ago
7

(99 POINTS) While driving her new Camaro at 20.0 m/s down a four-lane highway, Jessica comes up behind a slow-moving dump truck

and decides to pass in the left-hand lane. If Jessica can accelerate at a rate of 5.0 m/s2, how long will it take for her to reach a speed of 30.0 m/s?
Physics
2 answers:
Ede4ka [16]3 years ago
7 0

Answer:

To go from 20.0 to 30.0 m/s, that is a velocity change of 10.0 m/s.

From the definition of acceleration,

a = (velocity change)/(time required)

In this case you know that a = 5.0 m/s^2, so

time = (10.0 m/s)/(5.0 m/s^2)

= 2.0 seconds

julsineya [31]3 years ago
5 0

Answer:

2 seconds

Explanation:

There is a velocity change of 10.0 m/s.

a = (velocity change)/(time required)  

From this a = 5.0 m/s^2, so

time = (10.0 m/s)/(5.0 m/s^2)

= 2.0 seconds

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An airplane travels 4000m in 16 seconds on a heading of 35 whats is its velocity
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6 0
3 years ago
An electron is in motion at 4.0 × 106 m/s horizontally when it enters a region of space between two parallel plates, as shown, s
max2010maxim [7]

Answer:

xmax = 9.5cm

Explanation:

In this case, the trajectory described by the electron, when it enters in the region between the parallel plates, is a semi parabolic trajectory.

In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.

You use the Newton second law and the electric force on the electron:

F_e=qE=ma             (1)

q: charge of the electron = 1.6*10^-19 C

m: mass of the electron = 9.1*10-31 kg

E: magnitude of the electric field = 4.0*10^2N/C

You solve the equation (1) for a:

a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}

Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:

x_{max}=v_o\sqrt{\frac{2d}{a}}             (2)

Here, the height d is the distance between the plates d = 2.0cm = 0.02m

vo: initial velocity of the electron = 4.0*10^6m/s

You replace the values of the parameters in the equation (2):

x_{max}=(4.0*10^6m/s)\sqrt{\frac{2(0.02m)}{7.03*10^{13}m/s^2}}\\\\x_{max}=0.095m=9.5cm

The horizontal distance traveled by the electron is 9.5cm

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3 years ago
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Answer:

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lara [203]
The answer is B. It is locked up in glaciers and ice caps.

Hope this helped. Good luck! Please give me a thanks and Brainliest.
8 0
3 years ago
Read 2 more answers
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