Answer: D. the wave has traveled 97.2 cm in 1 second.
Explanation:
Got it right on edge, hope this helps :)
Answer:
![Q_T=63313.5\ J](https://tex.z-dn.net/?f=Q_T%3D63313.5%5C%20J)
Explanation:
Given:
- temperature of skin,
![T_s=34^{\circ}C](https://tex.z-dn.net/?f=T_s%3D34%5E%7B%5Ccirc%7DC)
- initial temperature of steam vapour,
![T_v=100^{\circ}C](https://tex.z-dn.net/?f=T_v%3D100%5E%7B%5Ccirc%7DC)
- latent heat of steam,
![L=2256\ J.g^{-1}](https://tex.z-dn.net/?f=L%3D2256%5C%20J.g%5E%7B-1%7D)
- mass of steam,
![m=25\ g](https://tex.z-dn.net/?f=m%3D25%5C%20g)
- specific heat of water,
![c=4190\ J.kg^{-1}.K^{-1}=4.19\ J.g^{-1}.K^{-1}](https://tex.z-dn.net/?f=c%3D4190%5C%20J.kg%5E%7B-1%7D.K%5E%7B-1%7D%3D4.19%5C%20J.g%5E%7B-1%7D.K%5E%7B-1%7D)
- final temperature,
![T_f=34^{\circ}C](https://tex.z-dn.net/?f=T_f%3D34%5E%7B%5Ccirc%7DC)
<em>Assuming that no heat is lost in the surrounding.</em>
<u>We know:</u>
![Q=m.c.\Delta T](https://tex.z-dn.net/?f=Q%3Dm.c.%5CDelta%20T)
<u>Now the total heat given by the steam to form water at the given conditions:</u>
..............................(1)
where:
latent heat given out by vapour to form water of 100°C
heat given by water of 100°C to come at 34°C.
putting respective values in eq. (1)
![Q_T=m(L+c.\Delta T)](https://tex.z-dn.net/?f=Q_T%3Dm%28L%2Bc.%5CDelta%20T%29)
![Q_T=25(2256+4.19\times 66)](https://tex.z-dn.net/?f=Q_T%3D25%282256%2B4.19%5Ctimes%2066%29)
![Q_T=63313.5\ J](https://tex.z-dn.net/?f=Q_T%3D63313.5%5C%20J)
is the heat transferred to the skin.
Answer:
3.7 km/h
Explanation:
Let's call v the proper speed of the boat and v' the speed of the water in the river.
When the boat travels in the direction of the current, the speed of the boat is:
v + v'
And it covers 50 km in 3 h, so we can write
(1)
When the boat travels in the opposite direction, the speed of the boat is
v - v'
And it covers 50 km in 5.4 h, so
(2)
So we have a system of two equations: by solving them simultaneously, we find the value of v and v':
![v+v'=16.7 \\v-v'=9.3](https://tex.z-dn.net/?f=v%2Bv%27%3D16.7%20%5C%5Cv-v%27%3D9.3)
Subtracting the second equation from the first one we get:
![(v+v')-(v-v')=16.7-9.3\\2v'=7.4\\v'=3.7](https://tex.z-dn.net/?f=%28v%2Bv%27%29-%28v-v%27%29%3D16.7-9.3%5C%5C2v%27%3D7.4%5C%5Cv%27%3D3.7)
So, the speed of the water is 3.7 km/h.
Answer:
frequency tell me if im right
Explanation:
Answer:
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