The upward normal force exerted by the floor is 620 N on an elevator passenger who weighs 650 N. Is the passenger accelerating?
1 answer:
Answer:
downward
Explanation:
There are two forces acting on the passenger on the elevator:
- The upward normal force, R
- The weight of the passenger, W
Therefore we can write Newton's second law as
where a is the acceleration of the passenger and m its mass. Here we took upward as positive direction, so that R is positive.
The mass of the passenger can also be written as
where g = 9.8 m/s^2 is the acceleration of gravity.
So the equation becomes
And solving for a, we find the acceleration:
and the negative sign means the direction is downward.
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Answer:
Yes, the paths of the two particles cross.
Location of path intersection = ( 1 , 2 , 3)
Explanation:
In order to find the point of intersection, we need to set both locations equal to one another. It should be noted however, that the time for each particle can vary as we are finding the point where the <u>paths</u> meet, not the point where the particles meet themselves.
So, we can name the time of the first particle , and the time of the second particle
.
Setting the locations equal, we get the following equations to solve for and
:
Equation 1
Equation 2
Equation 3
Solving these three equations simultaneously we get:
2 seconds
4 seconds
Since, we have an answer for when the trajectories cross, we know for a fact that they indeed do cross.
The point of crossing can be found by using the value of or
in the location matrices. Doing this for the first particle we get:
Location of path intersection = ( -1 + 2 , 4 - 2 , -1 + 2(2) )
Location of path intersection = ( 1 , 2 , 3)