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topjm [15]
3 years ago
7

How much dirt is there in a hole 3 feet deep, 6 ft long and 4 ft wide?

Physics
1 answer:
katrin [286]3 years ago
5 0
V = l x w x h
v = 3 x 6 x 4
v = 72
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Match the following: ​
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I matched the answers you requested above

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3 years ago
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Explain briefly where the energy come from when a liquid Rises against Gravity in a capillary tube​
SSSSS [86.1K]

Answer:

Surface tension

Explanation:

When liquid rises against gravity in a capillary tube, the energy comes from surface tension.

This is because surface tension is the energy that's needed to increase the liquid surface area.

As a result of hydrogen bonding present in Water, it usually has high surface tension which makes it to possess a tough skin that can make it not to break despite high forces applied to it.

The liquid will be in contact with the capillary tube and as such experiences surface tension which in turn makes the capillary tube to experience an upward force that makes the liquid begin to rise up.

The more the liquid keeps rising, the more it gets to the point where the surface tension becomes balanced from the weight of the liquid.

3 0
3 years ago
What is the car’s average velocity (in m/s) in interval between t=1.0s to t=1.5s?
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Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the formula for velocity is;

Velocity (in m/s) = distance/time

The distance the car covered in the completed question is divided by the difference in the time interval

The difference in the time interval will be = 1.5s - 1.0s = 0.5s

NOTE: the distance must be in meters or be converted to meters

7 0
3 years ago
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6 0
3 years ago
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A frictionless piston–cylinder device contains 5 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly accordin
Arte-miy333 [17]

Answer:

The work input during this process is -742 kJ

Explanation:

Given;

Initial temperature of nitrogen T₁ = 250 K

final temperature of nitrogen T₂ = 450 K

mass of nitrogen, m = 5 kg

PV^{1.4} = constant

The work input during the process is calculated as;

W = \frac{m*R(T_2-T_1)}{1-n}

where;

R is gas constant = 0.2968 kJ/kgK

substitute given values in above equation.

W = \frac{m*R(T_2-T_1)}{1-n} = \frac{5*0.2968(450-250)}{1-1.4} = -742 \ kJ

Therefore, the work input during this process is -742 kJ

8 0
4 years ago
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