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dalvyx [7]
3 years ago
9

A double-slit interference experiment shows fringes on a screen. The entire experiment is then immersed in water. Do the fringes

on the screen get closer together, farther apart, remain the same, or disappear entirely? Explain.
Physics
1 answer:
Otrada [13]3 years ago
4 0

Answer:

Get closer together

Explanation:

The refractive index of water is relatively than the refractive index of a vacuum or air. Due to the relationship between speed of light and refractive index, if the refractive index of the medium increases, the speed of light will decrease when the experiment is immersed in water. A reduction in the speed of light will lead to a decrease in wavelength. Mathematically the space between the fringes (Δy) is:

Δy = λ*L/d

Because the variables "L" and "d" are constants, a reduction in wavelength will lead to a reduction in Δy.

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A hot-air balloon and its basket are accelerating upward at 0.265 m/s2, propelled by a net upward force of 688 N. A rope of negl
Sergeu [11.5K]

Question:<em> </em><em>Find, separately, them mass of the balloon and the basket (incidentally, most of the balloon's mass is air)</em>

Answer:

The mass of the balloon is 2295 kg, and the mass of the basket is 301 kg.

Explanation:

Let us call the mass of the balloon m_1 and the mass of the basket m_2, then according to newton's second law:

(1). \:F = (m_1+m_2)a,

where a =0.265m/s^2 is the upward acceleration, and F = 688N is the net propelling force (counts the gravitational force).

Also, the tension T in the rope is 79.8 N more than the basket's weight; therefore,

(2). \:T = m_2g+79.8

and this tension must equal

T -m_2g =m_2a

(3). \:T = m_2g +m_2a

Combining equations (2) and (3) we get:

m_2a = 79.8

since a =0.265m/s^2, we have

\boxed{m_2 = 301.13kg}

Putting this into equation (1) and substituting the numerical values of F and a, we get:

688N = (m_1+301.13kg)(0.265m/s^2)

\boxed{m_1 = 2295 kg}

Thus, the mass of the balloon and the basket is  2295 kg and 301 kg respectively.

8 0
3 years ago
Find the right answer please
Ghella [55]

Answer:

3.78

Explanation:

bc ik it is :3

5 0
3 years ago
How much mass should be attached to a vertical ideal spring having a spring constant (force constant) of 39.5 n/m so that it wil
mrs_skeptik [129]
The frequency of a simple harmonic oscillator such as a spring-mass system is given by
f= \frac{1}{2 \pi}   \sqrt{ \frac{k}{m} }
where 
k is the spring constant
m is the mass attached to the spring.

Re-arranging the formula, we get:
m= \frac{k}{4 \pi^2 f^2}
and since we know the constant of the spring:
k=39.5 N/m
and the frequency of oscillation:
f=1.00 Hz
we can find the value of the mass attached to it:
m= \frac{39.5 Hz}{4 \pi^2 (1.00 Hz)^2} = 1.00 kg
7 0
3 years ago
What is the shape of a projectile
Cerrena [4.2K]
The answer I found was parabola?
8 0
3 years ago
Describe two reasons why scientists are looking for alternatives to fossil fuels
Evgesh-ka [11]
1) It is because they produce a lot of pollution in the atmosphere
2) They are limited in number and can't be recycled

Hope this helps!
3 0
3 years ago
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