All categories

3 years ago

How does the law of definite proportions apply to hydrates?

1 answer:

vladimir1956 [14]3 years ago

4 0

The law of definite proportions would state that a hydrate always contain exactly the same proportion of salt and water by mass.
strictly speaking, the law of definite proportion states that a compound always
contains exactly the same proportion of elements by mass.
But the law is often applied to groupings of elements in compound.
Hydrates are salt that have a certain amount of water asa part of their structure.
The water is chemically combined with the compound in a definite ratio.

You might be interested in

Which of the following compounds is a gas at room temperature? A : CH3CH2OH B : CH3CH2CH2CH2CH2CH2CH3 C : CH3CH2CH3 D : HOCH2CH2

attashe74 [19]

Answer:

C. $CH_3CH_2CH_3$

Explanation:

Molecules with the stronger intermolecular forces are pulled tightly together to form solid at higher temperatures and that's why the freezing point is higher.

Also, molecules with the stronger intermolecular force have greater interaction between the molecules and thus on heating do not boil easily and have high boiling point also.

Thus, melting point and boiling point increases with increase in number of carbon atoms and also increase in intermolecular forces (like hydrogen bonding, if present).

Thus, the compound which is gas at room temperature is $CH_3CH_2CH_3$ <u>because it has least number of carbon atoms and absence of hydrogen bonding.</u>

<u></u>

8 0

3 years ago

A rubber ball is held 4.0 m above a concave spherical mirror with a radius of curvature of 1.5 m. At time equals zero, the ball

exis [7]

The time elapsed when the ball placed above the concave mirror and the image formed would be at the same location is 0.55 s.

<h3>Image distance</h3>

The position of the image formed is determined using the followimg mirror formula;

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

where;

f is the focal length of the mirror
v is the image distance
u is the object distance

f = R/2

f = 1.5/2

f = 0.75 m

When the ball and its image is in the same position, u = v

The position of the ball is calculated as;

$\frac{1}{f} = \frac{1}{u} + \frac{1}{u} \\\\\frac{1}{f} = \frac{2}{u} \\\\u = 2f\\\\u = 2(0.75)\\\\u = 1.5 \ m$

<h3>Time of motion of the ball</h3>

The time taken for the ball to travel the caluclated distance is determined as;

h = ut + ¹/₂gt²

1.5 = 0 + ¹/₂(9.8)t²

1.5 = 4.9t²

t² = 1.5/4.9

t² = 0.306

t = 0.55 s

Thus, the time elapsed when the ball and its image are at the same location is 0.55 s.

Learn more about concave mirror here: brainly.com/question/7512320

8 0

2 years ago

Calculate the molarity of a solution prepared by dissolving 11.5 g naoh in enough water to make 1.5 l of solution.

Ronch [10]

Molar mass NaOH = 39.997 g/mol

Number of moles :

n = mass of solute / molar mass

n = 11.5 / 39.997

n = 0.287 moles

Therefore :

Molarity = moles solute / volume

Molarity = 0.287 / 1.5 => 0.1913 M

3 0

3 years ago

How does gas exchange work at diffusion level

Artist 52 [7]

. S s. A aa a. A abol

5 0

3 years ago

Based on the passage, which resources and organisms

AnnZ [28]

Answer:air, water, and organisms in water

Explanation:

read the passage