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3 years ago

Is fm radio a wave motion

Physics

1 answer:

Sedbober [7]3 years ago

8 0

I think you are asking if fm radio waves follow a wave motion and if so, the answer is yes

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One end of an elastic cord is fastened to a steel beam. A metal weight with a mass of 68 kg is attached to the other end of the

Vika [28.1K]

Hi there!

We can use IMPULSE to solve.

Recall impulse:

$I = \Delta p = m\Delta v = m(v_f - v_i)$

Begin by calculating the impulse. Assuming up to be the + direction, and down to be the - direction.

$I = 68(11 - (-14)) = 68 \cdot 25 = 1700 kg\frac{m}{s}$

Now, we can calculate force using this value:

$I = F \cdot t\\\\F = \frac{I}{t}\\\\F = \frac{1700}{0.85} = \boxed{2000 N}$

<u>The weight experiences a net force of 2000N UPWARDS.</u>

4 0

3 years ago

A high school physics instructor catches one of his students chewing gum in class. He decides to discipline the student by askin

kap26 [50]

Answer:

a) $\omega \approx 219.911\,\frac{rad}{s}$ , b) $\alpha = 16.916\,\frac{rad}{s^{2}}$ , c) $a_{t} = 1.776\,\frac{m}{s^{2}}$ , d) $a_{n} = 5077.889\,\frac{m}{s^{2}}$ , e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation, f) Zero, g) $v = 23.091\,\frac{m}{s}$ .

Explanation:

a) The maximum angular velocity of the fan is:

$\omega = (35\,\frac{rev}{s} )\cdot (\frac{2\pi\,rad}{1\,rev} )$

$\omega \approx 219.911\,\frac{rad}{s}$

b) The angular acceleration of the fan is:

$\alpha = \frac{\omega-\omega_{o}}{t}$

$\alpha = \frac{219.911\,\frac{rad}{s}-0\,\frac{rad}{s}}{13\,s}$

$\alpha = 16.916\,\frac{rad}{s^{2}}$

c) The magnitude of the tangential aceleration is:

$a_{t} = (16.916\,\frac{rad}{s^{2}} )\cdot (0.105\,m)$

$a_{t} = 1.776\,\frac{m}{s^{2}}$

d) The magnitude of the centripetal acceleration is:

$a_{n} = (219.911\,\frac{rad}{s} )^{2}\cdot (0.105\,m)$

$a_{n} = 5077.889\,\frac{m}{s^{2}}$

e) The direction of the centripetal acceleration experimented by the gum goes to the center of rotation.

f) When fan is at full speed, it rotates at constant rate and, hence, there is no angular acceleration. Besides, the tangential acceleration experimented by the gum is zero.

g) The linear speed of the gum is:

$v = (219.911\,\frac{rad}{s} )\cdot (0.105\,m)$

$v = 23.091\,\frac{m}{s}$

5 0

3 years ago

What is the weight of a rock that has a mass of 7kg?

sp2606 [1]

In pounds your answer is 15.4324 or 15.4

8 0

3 years ago

The heating element in a kettle behaves like a resistor. A particular kettle needs to operate at 230 V, with a power of 1500 W.

dedylja [7]

Answer:

R = 35.27 Ohms

Explanation:

Given the following data;

Voltage = 230V

Power = 1500W

To find the resistance, R;

Power = V²/R

Where:

V is the voltage measured in volts.

R is the resistance measured in ohms.

Substituting into the equation, we have;

1500 = 230²/R

Cross-multiplying, we have;

1500R = 52900

R = 52900/1500

R = 35.27 Ohms.

Therefore, the resistance which the heating element needs to have is 35.27 Ohms.

4 0

3 years ago

7. A 25 N block is lowered 1.2 m by a 20 N force.

Sauron [17]

Answer:

this answer your question

3 0

3 years ago