Question

Part A What width sit will produce a central maximum that is 2.50 em wide on a screen 2 20 m from the slit? Express your answer to three significant figures Green light (A 558 nm) strikes a single slit at normal incidence

Answer 1

Answer:

9.82×10⁻² m

Explanation:

w = Width of central maximum = 2.5 cm = 0.025 m

D = Distance between screen and slit = 2.2 m

λ = Wavelength of green light = 558 nm = 558×10⁻⁶ m

a = Width of slit

$w=\frac{2\lambda D}{a}\\\Rightarrow a= \frac{2\lambda D}{w}\\\Rightarrow a= \frac{2\times 558\times 10^{-6}\times 2.2}{0.025}\\\Rightarrow a= 98208\times 10^{-6}= 9.82\times 10^{-2}\ m$

∴ Width of slit is 9.82×10⁻² m