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Igoryamba
3 years ago
9

Please I really need help on this please help thank you

Physics
1 answer:
maw [93]3 years ago
4 0
What do you need help with?
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5.) How could we have improved this activity to be more precise?<br><br>ball on ramp ​​
AleksAgata [21]

Explanation:

I don't understand this question

could you please explain

7 0
3 years ago
When a .22-caliber rifle is fired, the expanding gas from the burning gunpowder creates a pressure behind the bullet. This press
mario62 [17]

Answer:

1.18454\times 10^{-19}\ Pa

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass of bullet = 2.6\times 10^{23}\ kg

r = Radius of barrel = 2.8\times 10^{23}\ m

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{370^2-0^2}{2\times 0.61}\\\Rightarrow a=112213.11475\ m/s^2

Pressure is given by

P=\dfrac{F}{A}\\\Rightarrow P=\dfrac{ma}{\pi r^2}\\\Rightarrow P=\dfrac{2.6\times 10^{23}\times 112213.11475}{\pi (2.8\times 10^{23})^2}\\\Rightarrow P=1.18454\times 10^{-19}\ Pa

The pressure of the expanding gas is 1.18454\times 10^{-19}\ Pa

7 0
3 years ago
What would you need to know to calculate the angular momentum of a man on a Ferris wheel?
valentinak56 [21]
The angular momentum calculated with respect to the axis of rotation of an object is given by:
L=mvr
where m is the object's mass, v is its tangential speed, and r is its distance from the axis of rotation.

In case of a man on a Ferris wheel, we need to have these quantities in order to calculate his angular momentum. These quantities corresponds to:
- m, the mass of the man
- v, the tangential speed of the wheel at its edge
- r, the radius of the wheel

It is possible to calculate the angular momentum even if we don't know v, the tangential speed. In this case, we need to know at least the angular velocity \omega (because from this relationship we can find the tangential speed: v=\omega r) or the period of rotation of the wheel, T (because we can find the angular velocity from it: \omega= \frac{2 \pi}{T}).
4 0
4 years ago
9 The friction between the car and the mud is equivalent to the__________________.
kakasveta [241]
Answer: e. None

Explanation: when the car goes into the muddy area, then the friction force on the tire is too small so the wheels are turned and slipped. Friction in this case is beneficial
5 0
3 years ago
What does m represent in the equation m = M+ 5 log(d/10)
melisa1 [442]
The lower case m =Apparent magnitude
5 0
3 years ago
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