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NISA [10]
2 years ago
15

If you were to compare three stars with the same surface temperature, with one star being a giant, another a supergiant, and the

third a main-sequence star, how would their radii compare to one another?
Physics
1 answer:
Fudgin [204]2 years ago
6 0

Answer:

Radii of Super giant > giant > main sequence star.

Explanation:

A star becomes a giant after all the hydrogen available for fusion, in a main sequence star is depleted and its outer shell of the star expands.

Super giant and giant stars are very large in size compared to a main sequence star. For example, if a giant star has 20 times the diameter of main sequence star, the super giant's diameter is almost 300 times or even more than a main sequence star.  

Most of the stars are main sequence stars. After a star has spent a few million or even a few billion years as a main sequence star, it becomes a giant and a super giant star. These are the later stages of development of development of the main sequence star. Giant and super giant phase of a star's life is very short compared to the main sequence star.

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A particle has a charge of -4.25 nC.
SpyIntel [72]

Answer:

-611.32 N/C

0.43723 m

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

q = Charge = -4.25 nC

r = Distance from particle = 0.25 m

Electric field is given by

E=\dfrac{kq}{r^2}\\\Rightarrow E=\dfrac{8.99\times 10^9\times -4.25\times 10^{-9}}{0.25^2}\\\Rightarrow E=-611.32\ N/C

The magnitude is 611.32 N/C

The electric field will point straight down as the sign is negative towards the particle.

E=\dfrac{kq}{r^2}\\\Rightarrow r=\sqrt{\dfrac{kq}{E}}\\\Rightarrow r=\sqrt{\dfrac{8.99\times 10^9\times 4.25\times 10^{-9}}{13}}\\\Rightarrow r=1.71436\ m

The distance from the electric field is 1.71436 m

4 0
3 years ago
Read 2 more answers
A particle is traveling in the positive direction along an x axis, at a constant 5 m/s. Which of the following
kvasek [131]
The particle will accelerate 5m/s every second until it reaches a maximum of whatever your graph/diagram goes to, I'm in physical science and this is somewhat similar to what I am doing now but I'm not sure if that was what your looking for.
8 0
3 years ago
What is the length of 0.005 mm in kilometers?
ZanzabumX [31]
The answer would be 5*10^9
.

If we divide \frac{5*10^9}{1*10^6}, it gives us 0.005!

Hope this helped! c:
4 0
3 years ago
Jak wpłynie na czas oczekiwania na pierwsze ogrzanie wody (pytanie 1) zwiększenie mocy
Kryger [21]

Answer:

so what are u saying

Explanation:

10x100=

5 0
3 years ago
Star X has an apparent magnitude of 1. Star Y has an apparent magnitude of 4. Both stars are in the same star cluster. Which sta
sashaice [31]

Answer:

Explanation:

From the given information:

Since both stars are in the same cluster, the magnitude and luminosity relationship can be calculated as:

m_1 - m_2 = -2.5 log _{10} (\dfrac{L_1}{L_2})

Given that;

m_1 = 1 and

m_2 = 4

Therefore,

1 - 4 = -2.5 log _{10} ( \dfrac{L_1}{L_2})

3 = -2.5 log _{10} ( \dfrac{L_1}{L_2})

Making \dfrac{L_1}{L_2} the subject of the formula:

\implies \dfrac{L_1}{L_2}= 10^{(\dfrac{3}{2.5})}

=15.84

≅ 16

Hence, we can conclude that star X is more luminous by a factor of 16

7 0
2 years ago
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