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Kruka [31]
3 years ago
12

Helium (density 0.18 kg/m^3 at 0°C and 1 atm pressure) remains a gas until the extraordinarily low temperature of 4.2 K.What is

the speed of sound in helium at 8 K?
Physics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

166.6396m/sec

Explanation:

Molar mass of helium = 4\times 10^{-3}kg/mole

\gamma for helium is 1.67

The velocity of helium in sound at any temperature is given by v=\sqrt{\frac{\gamma RT}{M}}=\sqrt{\frac{1.67\times 8.314\times 8}{4\times 10^{-3}}}=166.6396m/sec

R is a constant 8.314 atm\ mol^{-1}K^{-1}

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What usually happens to the host’s DNA during the lytic cycle?
VARVARA [1.3K]
The lytic cycle is one of the two phases of reproduction in viruses. In this part of reproduction, the viral RNA joins with the DNA of the host and copies itself into the host's DNA pattern. This will cause the host cells to reproduce the viral cells instead of the original host cells. Overtime as the viral cells continue to reproduce they will overload and eventually cause the host cell to explode. When this occurs, then the produced viruses will continue on to infect the next cell.
6 0
3 years ago
The human ear canal is about 2.9 cm long and can be regarded as a tube open at one end and closed at the eardrum. What is the fu
zhenek [66]

Answer:

f=2887.93Hz

Explanation:

Given data

Length L=2.9 cm=0.029m

Speed of sound v=335 m/s

to find

Fundamental frequency f

Solution

As we know that frequency is given as:

f=v/λ

f=\frac{v}{4L}\\ f=\frac{335m/s}{4(0.029m)} \\ f=2887.93Hz

3 0
3 years ago
Joe is measuring the time it takes for a ball to roll down a ramp. In this experiment Joe takes the measurement 5 times and gets
PolarNik [594]

 Step by step solution :

standard deviation is given by :

\sigma = \sqrt\dfrac{{\sum (x-\bar{x})^2}}{n}

where, \sigma is standard deviation

\bar{x} is mean of given data

n is number of observations

From the above data, \bar{x}=24.88

Now, if x=24.8, then (x-\bar{x})^2=0.0064

If  x=23.9, then (x-\bar{x})^2=0.9604

if x=26.1, then (x-\bar{x})^2=1.4884

If x=25.1, then (x-\bar{x})^2=0.0484

If x=24.5, then (x-\bar{x})^2=0.1444

so, \sum (x-\bar{x})^2 =\frac{0.0064+0.9604+1.4884+0.0484+0.1444}{5}

\sum (x-\bar{x})^2 =2.648

\sqrt{\sum \frac{(x-\bar{x})^2}{n}}

\sigma =0.7277

No, Joe's value does not agree with the accepted value of 25.9 seconds. This shows a lots of errors.

6 0
3 years ago
Once a baseball has been hit into the air, what forces are acting upon it? How can you tell that any forces are acting upon the
Tom [10]
Well, its in the air, so the air is "upon" the ball. and when it comes down...you catch it, and throw it, and get someone out, and win the game, and just keep doing that, and boooommm you're and pro baseball player. Life is good
8 0
3 years ago
A charge +1.9 μC is placed at the center of the hollow spherical conductor with the inner radius 3.8 cm and outer radius 5.6 cm.
Archy [21]

To solve this problem we will apply the concepts related to load balancing. We will begin by defining what charges are acting inside and which charges are placed outside.

PART A)

The charge of the conducting shell is distributed only on its external surface. The point charge induces a negative charge on the inner surface of the conducting shell:

Q_{int}=-Q1=-1.9*10^{-6} C. This is the total charge on the inner surface of the conducting shell.

PART B)

The positive charge (of the same value) on the external surface of the conducting shell is:

Q_{ext}=+Q_1=1.9*10^{-6} C

The driver's net load is distributed through its outer surface. When inducing the new load, the total external load will be given by,

Q_{ext, Total}=Q_2+Q_{ext}

Q_{ext, Total}=1.9+3.8

Q_{ext, Total}=5.7 \mu C

5 0
4 years ago
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