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Sedimentary rocks also known as clastic sedimentary rock
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Answer:
500J
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Taking specific heat of lead as 0.128 J/gK = c
We have energy of ball at 7.00 meter height = mgh = 
When leads gets heated by a temperature ΔT energy needed = mcΔT
=
ΔT
Comparing both the equations
=
ΔT
ΔT = 0.536 K
Change in temperature same in degree and kelvin scale
So ΔT = 0.536 