Answer:
Explanation:
We know that the work could be calculate dby:
W =
where is the component of the force in the direction of the
displacement. and d is the displacement.
So, the total work () is:
Where is the force done by the first tugboat, is the angle of the force, d is the displacement and is the force done by the second tugboat.
Answer:
a) 431 Hz
b) 429 Hz
c) 403 Hz
Explanation:
The frequency you heard is calculated using the relation
f = f(s) / [1 - (v(s)/v) ]
f = 400 / [1 - 25/343]
f = 400 / (1 - 0.0729)
f = 400 / 0.9271
f = 431.5 Hz
The frequency your friend starts hearing is
f = f(s) * [1 + (v(s)/v) ]
f = 400 * [1 + 25/343]
f = 400 * (1 + 0.0729)
f = 400 * 1.0729
f = 429.2 Hz
when you're next to each other and you are hearing 3 beats per second. The frequency you're singing is 400 + 3 Hz
403 Hz
Answer:
Energy = Power × Time
We make Time the subject in this equation
Time = Energy ÷ Power
Time = 10000 ÷ 400
Time = 25seconds
The distance travelled by the ball that is thrown horizontally from a window that is 15.4 meters high at a speed of 3.01 m/s is 5.34 m
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
Vertically,
s = 15.4 m
u = 0
a = 9.8 m / s²
15.4 = 0 + ( 1 / 2 * 9.8 * t² )
t² = 3.14
t = 1.77 s
Horizontally,
u = 3.01 m / s
a = 0 ( Since there is no external force )
s = ( 3.01 * 1.77 ) + 0
s = 5.34 m
Therefore, the distance travelled by the ball before hitting the ground is 5.34 m
To know more about distance travelled
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Answer:
15.5 seconds
Explanation:
Apply Newton's second law:
∑F = ma
-12500 + 9200 = (12000) a
a = -0.275 m/s²
v = at + v₀
0 = (-0.275) t + 4.25
t = 15.5 s
It takes the boat 15.5 seconds to stop.