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Anon25 [30]
3 years ago
10

How many moles of oxygen atoms are contained in the following? 1.67 x 10-2mol CuSO4-5 H₂O

Chemistry
1 answer:
ivanzaharov [21]3 years ago
4 0
This may help you.
1. Calculate molecular mass of CuSO4•5H2O 2. Calculate molecular mass of ALL oxygen atoms in CuSO4•5H2O (which are 4 oxygen atoms in CuSO4 and 5 oxygen atoms in H2O so in total its 9 oxygen atoms, thus find molecular mass if 9 oxygen atoms) 3. Do mathematical cross multiplication Molecular mass of CuSO4•5H2O - <span>1.67×<span>10<span>−2</span></span>moles</span> molecular mass of 9 oxygen atoms - X moles so X= <span>1.67×<span>10<span>−2</span></span>moles</span><span> * molecular mass of 9 oxygen atoms / Molecular mass of CuSO4•5H2 and get the answer :3</span>
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Answer: The final pressure is 75 mm Hg.

Explanation:

According to Boyle's law, at constant temperature the pressure of a gas in inversely proportional to volume.

Since, it is given that the temperature is constant. Hence, formula used is as follows.

P_{1}V_{1} = P_{2}V_{2}

Substitute the values into above formula as follows.

P_{1}V_{1} = P_{2}V_{2}\\750 mm Hg \times 2 L = P_{2} \times 20 L\\P_{2} = \frac{750 mm Hg \times 2 L}{20 L}\\= 75 mm Hg

Thus, we can conclude that the final pressure is 75 mm Hg.

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6 0
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