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coldgirl [10]
4 years ago
9

Compared to the force needed to start sliding a crate across a rough level floor, the force needed to keep sliding once it is mo

ving is
1) less

2) greater

3) the same
Physics
2 answers:
san4es73 [151]4 years ago
3 0

The force to start sliding a crate across a rough level uses the equation:

F_f = \mu_sN

The force to keep it moving is given by:

F_f = \mu_dN

Notice that <em>N</em> or the Normal Force stays constant because it's the same object throughout the experiment and angle of the ground is also constant. Therefore, only thing that makes a differences are the static and dynamic coefficients of friction. The comparison between them is given by the law:

\mu_s \geq \mu_d

Therefore, the force needed to start sliding a crate across a rough level floor is <em><u>greater</u></em> than the force needed to keep it sliding once it is moving. So, your answer is <u>2</u>.

Hope I could help! :)

USPshnik [31]4 years ago
3 0

Answer:

Greater

Explanation:

As we know that when an object is placed on a rough floor then minimum force required to slide the object on the rough surface is known as limiting friction force.

Limiting friction is the maximum value of static friction between the object and ground surface.

So it is given as

f_s = \mu_sF_n

Once the object start sliding on the rough surface then the friction force on the object is known as kinetic friction which is given by

f_k = \mu_kF_n

now we know that

\mu_s \geq \mu_k

So it requires less force to move an object on rough floor once it starts sliding

So the force required to start sliding is greater than the force to move it once it start sliding

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When a satellite is revolving into the orbit around a planet then we can say

net centripetal force on the satellite is due to gravitational attraction force of the planet, so we will have

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3 years ago
One timing problem in using fiscal policy to counter a recession is the "legislative lag" that occurs between the
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4 0
3 years ago
A weight lifter lifts a dumbbell a certain height in 2.0 s, while a competitor does the same workin 1.0 s. Compared to the power
Aloiza [94]

Answer:

a. one-half as great

Explanation:

The power developed by the first lifter is one-half as great as that of the second person.

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Since the two lifters do the same work at different time, let us estimate their power;

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4 0
3 years ago
When the voltage across a steady resistance is doubled, the current?
natima [27]

I'm actually going ahead in the book (DC Circuits) so this isn't really homework but I figured the tag was appropriate....the name of the chapter is Ohm's Law and Watt's Law.

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The next question is what I'm not sure about:

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What I did initially was: P = IV = (100mA)(2V) = 2 W

But then I looked at the answer and it said 4 W, then I looked at the Hint again. Then I remembered in the book early on it said "If the voltage increases across a resistor, current will increase."

So question is: When solving problems I have to increase (or decrease) current (I) every time voltage (V) is increased (decreased) in a problem, right? How about the other way around, when increasing current (I), you need to increase voltage (V). I'm pretty sure that's how they got 4 W, but want to make sure before I head to the next section of the book.

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8 0
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Marianna [84]

Answer : When a person applies force and covers distance then the person is doing work on an object.

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