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Nataliya [291]
3 years ago
5

Solution A and solution B are separated by a semipermeable membrane. Solution A contains 1% glucose, solution B contains 5% gluc

ose. By diffusion: Solution A and solution B are separated by a semipermeable membrane. Solution A contains 1% glucose, solution B contains 5% glucose. By diffusion: water will move from solution A to solution B. glucose will move from solution B to solution A. water will move from solution B to solution A. glucose will move from solution A to solution B.
Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

Glucose will move from the solution B to the solution A

Explanation:

Given that:

Solution A contains 1% glucose, and,

Solution B contains 5% glucose

Diffusion is the net movement of the substance from the region of the higher concentration to the region of the lower concentration.

Thus, solution B contains more concentration of glucose as compared to solution A. <u>By the process of diffusion, the particle moves from higher concentration to lower concentration and thus, glucose will move from solution B to solution A.</u>

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Chlorophyll a is one of the green pigments found in plants. Chlorophyll a has the molecular formula C55H72MgN4O5. How many atoms
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3 years ago
Water in ethanol solution which one of them is solvent?​
ANEK [815]

Answer:

The mixture of ethanol and water is a liquid-liquid solution. The solvent is Water.

Explanation:

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Consider the reaction between a solution of molecule A and a solid block of molecule B. In general, for a reaction to occur, the
Blababa [14]

Answer:

Decreasing the volume of solvent in the solution of molecule A

Explanation:

We know that one of the factors that affect the rate of reaction is the concentration of the reactants. The greater the concentration of reactants, the faster the rate of reaction (the greater the frequency of collision between reactants).

Hence, when we decrease the volume of solvent in the solution of molecule A, the concentration of the solution increases and consequently more particles of molecule A are available to collide with particles of molecule B resulting in a higher rate of reaction.

3 0
3 years ago
Calculate δs∘rxn for the reaction2no(g) o2(g)→2no2(g)express your answer to one decimal place and include the appropriate units
Anna35 [415]

The δs∘rxn  for the reaction 2NO(g) + O_{2} → 2NO_{2} (g) will be -146 J/K.

Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.

Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit JK^{-1} mol^{-1}.

Entropy of the reaction can be calculated by the reaction.

ΔS^{0} rxn = 2 mol × S^{0} (NO_{2} (g) - 2 mol × S^{0} NO (g) - 1 mol × S^{0} (O_{2} )

ΔS^{0} rxn  = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol  ×205.2 J/mol.K

ΔS^{0} rxn  = -146.8 J/K

Therefore, the δs∘rxn  for the reaction 2NO(g) + O_{2} → 2NO_{2} (g) will be -146 J/K.

To know more about reaction

brainly.com/question/20305735

#SPJ4

4 0
1 year ago
You have 4 moles of oxygen gas in a flask. 4 moles of helium gas is added. What happens to the total pressure of the gases in th
ASHA 777 [7]

Answer: The correct option is (c). The total pressure doubles.

Solution:

Initially,  only 4 moles of oxygen gas were present in the flask.

p_{O_2}=Tp_1\times X_{O_2}  (X_{O_2}=\frac{4}{4}) ( according to Dalton's law of partial pressure)

p_{O_2}=Tp_1\times 1=Tp_1....(1)

Tp_1= Total pressure when only oxygen gas was present.

Final total pressure when 4 moles of helium gas were added:

X'_{O_2}=\frac{4}{8}=\farc{1}{2},X_{He}=\frac{4}{8}=\frac{1}{2}

partial pressure of oxygen in the mixture :

Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

p_{O_2}=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

Tp_2= Total pressure of the mixture.

from (1)

Tp_1=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

On rearranging, we get:

Tp_2=2\times Tp_1

The new total pressure will be twice of initial total pressure.

7 0
3 years ago
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