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Nataliya [291]
3 years ago
5

Solution A and solution B are separated by a semipermeable membrane. Solution A contains 1% glucose, solution B contains 5% gluc

ose. By diffusion: Solution A and solution B are separated by a semipermeable membrane. Solution A contains 1% glucose, solution B contains 5% glucose. By diffusion: water will move from solution A to solution B. glucose will move from solution B to solution A. water will move from solution B to solution A. glucose will move from solution A to solution B.
Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

Glucose will move from the solution B to the solution A

Explanation:

Given that:

Solution A contains 1% glucose, and,

Solution B contains 5% glucose

Diffusion is the net movement of the substance from the region of the higher concentration to the region of the lower concentration.

Thus, solution B contains more concentration of glucose as compared to solution A. <u>By the process of diffusion, the particle moves from higher concentration to lower concentration and thus, glucose will move from solution B to solution A.</u>

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In Methyl Amine the Nitrogen atom is attached to two Hydrogen Atoms and one Methyl (CH₃-) group. From Lewis structure it is shown that the Nitrogen atom also contains a lone pair of electron.
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According to Valence Shell Electron Pair Repulsion (VSEPR) Theory, those central atoms which have four electron pairs and all of them are bonding electron pairs gives Tetrahedral Geometry.

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3 years ago
An unknown metal with a mass of 54.0 g required 773 J of energy in order to change its temperature from 63.0 C to 100.0 C. What
Vitek1552 [10]

Answer:

Metal is copper.

Explanation:

Mass of a metal, m = 54 g

Heat energy required, Q = 773 J

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We need to identify the metal. Heat required to raise the temperature is given by :

Q=mc\Delta T

c is specific heat of the metal

We can identify the metal by finding its specific heat.

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{773}{54\times (100-63)}\\\\=0.386\ J/g^{\circ} C

The metal is copper. Its specific heat is 0.386\ J/g^{\circ} C.

8 0
3 years ago
Calculate the solubility (in M) of cobalt(II) hydroxide, Co(OH)2(s) in H2O. Ksp = 1.10×10-16 at a specific temperature.
Oksanka [162]

Answer:

3.018 x 10⁻⁶ M.

Explanation:

  • Co(OH)₂ dissociates in solution according to the equation:

<em>Co(OH)₂ →</em> <em>Co²⁺ + 2OH⁻.</em>

<em></em>

<em>∵ Ksp = [Co²⁺][OH⁻]² = (s)(2s)² = 4s³.</em>

<em />

∴ 4s³ = 1.10 x 10⁻¹⁶.

∴ s³ = 1.10 x 10⁻¹⁶/4 = 2.75 x 10⁻¹⁷.

∴ s = ∛(2.75 x 10⁻¹⁷) = 3.018 x 10⁻⁶ M.

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zubka84 [21]
D for sure hope this helps
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