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Leviafan [203]
3 years ago
12

Butane - ethane - methane - propane: What do these hydrocarbons have in common?

Chemistry
1 answer:
Kobotan [32]3 years ago
8 0

Answer:

Both have in common that they are alkanes.

Explanation:

hey represent hydrocarbons, that is to say organic compounds that contain atoms of Carbon and Hydrogen. The termination (suffix) -ano refers to alkanes.

Methane: has a carbon atom, Ethane: 2, Propane: 3 and Butane: 4.

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How many grams of glucose (C6H12O6) can be formed from 22 grams of CO2?
Shkiper50 [21]
The catabolism of glucose has an equation of C6H12O6 + 6O2 = 6CO2 +6 H20. Hence for every mole of glucose, 6 moles of CO2 is produced. Given 22 grams of CO2, that is 0.5 mol CO2, we multiply this by 1/6, we get the number of moles of glucose equal to 1/12 mol. The mass of glucose needed is obtained by multiplying this by molar mass of glucose which is 180 g/mol. This is equivalent 15 grams of glucose.
8 0
3 years ago
Use the ideal gas law to calculate the pressure in atmospheres of 0.21 mol of helium (He) at 16°C & occupying 2.53 L. You mu
chubhunter [2.5K]

Answer:

The answer to your question is 2.32 atm

Explanation:

Data

P = ?

n = 0.214

V = 2.53 L

T = 61°C

R = 0.082 atm L/mol°K

Formula

PV = nTR

solve for P

P = nRT/V

Process

1.- Calculate the temperature in K

°K = °C + 273

°K = 61 + 273

    = 334

2.- Substitution

P = (0.214 x 0.082 x 334) / 2.53

3.- Simplification

P = 5.86/2.53

4.- Result

P = 2.32 atm

4 0
3 years ago
Explain the connection between atoms and electricity
zaharov [31]

Answer:

The protons and electrons of an atom are attracted to each other. They both carry an electrical charge. Protons have a positive charge (+) and electrons have a negative charge (-). The positive charge of the protons is equal to the negative charge of the electrons.

Explanation:

8 0
2 years ago
Changes in appearance...
Serjik [45]
I'm not quite sure but I think if you field the corner or cut it it would physically change it while not creating something new (chemical change).
3 0
4 years ago
How does plaster efect the strength of wood?
Tatiana [17]
<span>In this work the performance of gypsum plaster and wood particle in pastes and composites was investigated. Wood particles of fineness 0.42 mm and 1.20 mm were employed. Natural wood particles and the treated ones in cold or hot water (80 °C) were performed. The effects of the extractives solutions from the treatments applied to the wood particles on wood-gypsum compatibility were studied. For pastes and composites, water-to-gypsum ratio was 0.65. Wood particles-to-gypsum plaster ratios were 5%, 10% and 15%, in mass. Kinetics of temperature, mechanical performance and dynamic elasticity modulus by ultrasound measurements were applied to evaluate the gypsum plaster pastes and its composites behaviors. Results show that the extractive solutions changed the time of gypsum plaster hydration, being more sensitive to hot water treatment. The composites compressive strength increase with the wood particles pretreatment. The best result was to room temperature treatment. The same performance was found to the modulus of elasticity. Treatments have improved significantly the flexural strength. The best wood particle content was 10%. These results show the possibility of using this wood waste with an easy and simple treatment to make eco-efficient building materials.</span>
7 0
4 years ago
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