Answer:
<em>The</em><em> </em><em>Typical</em><em> </em><em>Oxidation</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>Oxygen</em><em> </em><em>is</em><em> </em><em>–</em><em>2</em><em>.</em>
<em>And</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>question</em><em> </em><em>said</em><em>.</em><em>.</em><em>.</em><em> </em><em>its</em><em> </em><em>Oxidation</em><em> </em><em>changes</em><em> </em><em>to</em><em> </em><em>–</em><em>1</em><em> </em><em>when</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>in</em><em> </em><em>Peroxides</em><em> </em><em>and</em><em> </em><em>–</em><em>½</em><em> </em><em>w</em><em>h</em><em>e</em><em>n</em><em> </em><em>i</em><em>t</em><em>s</em><em> </em><em>i</em><em>n</em><em> </em><em>SuperOxides</em><em>.</em>
<em>Correct</em><em> </em><em>Answer</em><em> </em><em>:</em><em> </em><em>Option</em><em> </em><em>D</em><em>.</em>
Answer:
P1 = 2.5ATM
Explanation:
V1 = 28L
T1 = 45°C = (45 + 273.15)K = 318.15K
V2 = 34L
T2 = 35°C = (35 + 273.15)K = 308.15K
P1 = ?
P2 = 2ATM
applying combined gas equation,
P1V1 / T1 = P2V2 / T2
P1*V1*T2 = P2*V2*T1
Solving for P1
P1 = P2*V2*T1 / V1*T2
P1 = (2.0 * 34 * 318.15) / (28 * 308.15)
P1 = 21634.2 / 8628.2
P1 = 2.5ATM
The initial pressure was 2.5ATM
Answer:
Answer is A
Explanation:
Now we know that an atom wants to complete its outer shell while keeping electrons in pairs of two now in A there are four electrons which which can be ejected while in B will want to accept 3 electrons to complete its shell as ejecting five will take lot of energy similar case will be for C,D and E which would want to accept 2,1,0 electrons respectively
Answer:
You'll experience a grater deviation
Explanation:
<em>You'll experience a greater deviation in your measurements, meaning your measures will have a bigger difference between them, and the greater these deviations the less accurate will be the measuring.</em> This happens mainly because you're not replicating the measurement with the exact same conditions, in one of them you'll have an extra mass from the water.
I hope you find this information useful and interesting! Good luck!
Answer:
18,1 mL of a 0,304M HCl solution.
Explanation:
The neutralization reaction of Ba(OH)₂ with HCl is:
2 HCl + Ba(OH)₂ → BaCl₂ + 2 H₂O
The moles of 17,1 mL≡0,0171L of a 0,161M Ba(OH)₂ solution are:
= 2,7531x10⁻³moles of Ba(OH)₂
By the neutralization reaction you can see that 2 moles of HCl reacts with 1 mole of Ba(OH)₂. For a complete reaction of 2,7531x10⁻³moles of Ba(OH)₂ you need:
= 5,5062x10⁻³moles of HCl.
The volume of a 0,304M HCl solution for a complete neutralization is:
= 0,0181L≡18,1mL
I hope it helps!