Which of these changes do ot involve forming or breaking chemical bonds?

my friend wore a smart watch to bed,when he woke up in the morning it showed 300 steps taken how did this happen?

Ghella [55]

Answer:

Your tracker will detect your arm movement and will interpret it as steps so this is what it likely happening. Something similar happens while driving, if you go through a bumpy road or your car has a stiff suspension then this can cause the tracker to detect movement and count it as steps. Usually while driving and if you notice some vibration on your car or steering wheel you can try having your tracker a little bit more tight around your wrist and this will help decrease the amount of steps detected.

Explanation:

(Via AlvaroFitbit)

3 0

3 years ago

When a psychologist is making a determination regarding whether or not a study is ethical, one should first consider __________

Rasek [7]

Healthy and strong people

6 0

4 years ago

A sling-thrower puts a stone (0.250 kg) in the sling’s pouch (0.010 kg) and then begins to make the stone and pouch move in a ve

IrinaK [193]

Answer:

The cord will break at the lower point.

The linear velocity:

$V=8,72m/s$

Explanation:

The cord will break at the lower point, as this point is where the maximum tension will be at any given speed. This is because at the lower point to maintain the circular movement the cord must withstand the centripetal force plus the gravity force that goes on the opposite direction. To explain this, to maintain the circular movement the stone must always be subjected to a resultant force equal to the centripetal force:

(1) $F_{T}=F_{c}=m*r*w^{2}$

This is constant for a given speed and radius. The total force is the sum of all the forces on the stone, in this case the gravitational force(W) and the cord tension(T). On the upper point they are on the same direction:

$F_{TU}=F_{c}=T+W => T=F_{c}-W$

On the lower point they have opposite directions:

(2) $F_{TL}=F_{c}=T-W => T=F_{c}+W$

As the centripetal force and weight are constant for a given speed and radius, the tension on the lower point is bigger.

As the cord will break at 33N at the lower point, from (2):

$T=F_{c}+W=33N$

$F_{c}=33N-W=33N-(0,25kg+0,01kg)*9,8m/s^{2}=30,45N$

replacing on (1):

$F_{c}=30,45N=m*r*w^{2}$

$w=\sqrt{\frac{30,45N}{m*r} } =\sqrt{\frac{30,45N}{0,26kg*0,65m} } =13,42/s$

The linear velocity:

$V=w*r=13,42/s*0,65m=8,72m/s$

7 0

3 years ago

An orchestra is practicing a piece that is to be played at an allegro tempo. The conductor sets a metronome at 160 beats per min

MariettaO [177]

To develop this problem it is necessary to apply the concepts related to the Frequency according to the Period. Frequency is the number of repetitions per unit of time of any periodic event. The period is the length of time of each repetitive event, so the period is the reciprocal of the frequency.

The frequency of the metronome in seconds would then be

$f = 160 \frac{beats}{min} (\frac{1min}{60s})$