Answer:
The first force that the bungee jumper experiences is gravity, which pulls down on everything and makes the jumper fall. The gravitational force is almost exactly constant throughout the jump. During the bungee jumper's fall, he or she also experiences a force due to air resistance.
Explanation:
Answer:
2.5 cm
Explanation:
Number of spins in 12 seconds = 18
Number of spins in 1 second = 18 / 12 = 1.5
Number of spins in one second is called frequency.
f = 1.5 rps
ac = 2.2 m/s^2
Let r be the radius of coin
Centripetal acceleration, ac = r x w^2
2.2 = r x ( 2 x 3.14 x 1.5) ^2
2.2 = r x 88.7364
r = 0.025 m = 2.5 cm
Answer:
Explanation:
Yesterday before i texted you it was like 11:00 and me and my friends were at the park and we were talking and there were like three boys and they came u to us and they said guess are size and i was like shoe size ? and they were like n ah you know what what i mean i just said i d k like how would i know and than my friend told them i was a v irgin and the may be like 30 min after they kept talking i just said im tired so i was going home and they invited them to there houses boys are like so weird in LA
Answer:
Explanation:
Electric field E = 4 x 10⁷ V / m
Dielectric constant k = 24
capacitance of capacitor
C = kε₀ A / d
d = plate separation
A = plate area
C = .89 x 10⁻⁶
V / d = electric field
for minimum d , electric field will be maximum
V / d = 4 x 10⁷
1930 / d = 4 x 10⁷
d = 1930 / 4 x 10⁷
d = 482.5 x 10⁻⁷ m
= 48.25 x 10⁻⁶ m
C = kε₀ A / d
.89 x 10⁻⁶ = 24 ε₀ A / d
A = .89 x 10⁻⁶ X d / 24 ε₀
A = .89 x 10⁻⁶ X 48.25 x 10⁻⁶ / 24 x 8.85 x 10⁻¹²
= 42.9 / 212.4
= .2019 m²
Answer:
Explanation:
given that
Radius =0.75m
Cnet=0.13nC
a. Electric field inside the sphere located 0.5m from the center of the sphere.
The electric field located inside the sphere is zero.
b. The electric field located 0.25m beneath the sphere.
Since the radius is 0.75m
Then, the total distance of the electric field from the centre of the circle is 0.75+0.25=1m
Then
E=kq/r2
K=9e9Nm2/C2
q=0.13e-9C
r=1m
Then,
E= 9e9×0.13e-9/1^2
E=1.17N/C. Q.E.D
