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Viefleur [7K]
4 years ago
10

The largest and smallest slits in these experiments are 0.16mm and 0.04mm wide,respectively. The wavelength of the laser light i

s 650nm. How many wavelengthswide are these slits?
Physics
1 answer:
pishuonlain [190]4 years ago
7 0

Answer:

Explanation:

Answer:

The slits are 246 and 62 wavelengths wide, respectively.

Explanation:

Given that there are two slits:

the largest slit = x1 = 0.16mm or 0.00016m wide

the smallest slit = x2 = 0.04mm or 0.00004m wide, and

the wavelength of laser light = λ = 650nm or 650 × 10˄—9m

(a) the largest slit is X wavelengths wide where X = x1/ λ

Therefore, X = 0.00016m/650 × 10˄—9m = 246 wavelengths

(b) the smallest slit is X1 wavelengths wide, where X1 = x2/ λ

Therefore, Y = 0.00004m/650 × 10˄—9m = 62 wavelengths

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The work done on the filled bucket in raising out of the hole is 2, 925 Joules

<h3>How to determine the work done</h3>

Using the formula:

Work done = force * distance

Note that force = mass * acceleration

F = mg + ma

F = 4. 5 * 10 + 28 * 10

F = 45 + 280

F = 325 Newton

Distance = 9m

Substitute into formula

Work done = 325 * 9

Work done = 2, 925 Joules

Therefore, the work done is 2, 925 Joules

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4 0
2 years ago
A student is given a red and a blue liquid. The two samples of liquids are
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<h3>Option D) The red liquid has a smaller specific heat</h3>

When a substance has smaller specific heat it needs less heat to shows changes in it hence making the option D correct.

3 0
3 years ago
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To test the quality of a tennis ball, you drop it onto the floor from a height of 4.00 m. It rebounds to a height of 2.00 m. If
arlik [135]

Answer:

Part a)

a = 1260.3 m/s^2

Part b)

Direction = upwards

Explanation:

When ball is dropped from height h = 4.0 m

then the speed of the ball just before it will strike the ground is given as

v_f^2 - v_i^2 = 2 a d

v_1^2 - 0^2 = 2(9.81)(4.0)

v_1 = 8.86 m/s

Now ball will rebound to height h = 2.00 m

so the velocity of ball just after it will rebound is given as

v_f^2 - v_i^2 = 2 a d

0 - v_2^2 = 2(-9.81)(2.00)

v_2 = 6.26 m/s

Part a)

Average acceleration is given as

a = \frac{v_f - v_i}{\Delta t}

a = \frac{6.26 - (-8.86)}{12.0 \times 10^{-3}}

a = 1260.35 m/s^2

Part B)

As we know that ball rebounds upwards after collision while before collision it is moving downwards

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7 0
3 years ago
Using monochromatic light of 410 nm wavelength, a single thin slit forms a diffraction pattern, with the first minimum at an ang
VLD [36.1K]

Answer:

c. 307 nm

Explanation:

angular position of first dark fringe =  λ / d ,   λ is wavelength and  d is width of slit .

(40 x π ) / 180 = 410 / d

angular position of second  dark fringe =  2 x λ / d ,   λ is wavelength and  d is width of slit .

(60 x π ) / 180 = 2 x λ / d

Dividing these equations

60 / 40 =  2 x λ / 410

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5 0
4 years ago
The magnitude of the electric force between two protons is 2.30 10-26 n. how far apart are they?
SCORPION-xisa [38]
The electric force between two charge objects is calculated through the Coulomb's law.
                               F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
                           2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m. 
7 0
3 years ago
Read 2 more answers
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