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VMariaS [17]
3 years ago
8

Question 10(Multiple Choice Worth 2 points)

Physics
2 answers:
Sunny_sXe [5.5K]3 years ago
4 0

D. 0.05 kg•m/s

Just multiply the two numbers :)

Please mark brainliest!

Svetach [21]3 years ago
3 0
P = mv

P momentum
m mass
v velocity
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Four wires are made of the same highly resistive material, cut to the same length, and connected in series. Wire 1 has resistanc
Paraphin [41]

Answer:

V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}

Explanation:

The 4 wires are connected in series: this means that the same current flow through them, and the voltage of the battery, V0, is equal to the sum of the voltages on each individual resistor:

V_0=V_1+V_2+V_3+V_4

Also, the equivalent resistance of the series circuit is

R_{eq}=R_1+R_2+R_3+R_4

The voltage V2 across wire 2 is given by Ohm's law:

V_2 = R_2 I (1)

where I is the total current in the circuit, which is given by:

I=\frac{V_0}{R_{eq}}=\frac{V_0}{R_1+R_2+R_3+R_4}

Substituting this into eq. (1), we find an expression for V2:

V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}

8 0
3 years ago
Find the ratio of the new/old periods of a pendulum if the pendulum were transported from earth to the moon, where the accelerat
vichka [17]
The period of a pendulum is given by
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the pendulum length and g is the gravitational acceleration.

We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
\frac{T_m}{T_e} =  \frac{2 \pi  \sqrt{ \frac{L}{g_m} } }{2 \pi  \sqrt{ \frac{L}{g_e} } }=    \sqrt{ \frac{g_e}{g_m} }
where the labels m and e refer to "Moon" and "Earth".

Since the gravitational acceleration on Earth is g_e = 9.81 m/s^2 while on the Moon is g_m=1.63 m/s^2, the ratio between the period on the Moon and on Earth is
\frac{T_m}{T_e}= \sqrt{ \frac{g_e}{g_m} }= \sqrt{ \frac{9.81 m/s^2}{1.63 m/s^2} }=2.45

3 0
2 years ago
How many moles of MgCl2 are there in 315 g of the compound? mol
jeka94
315g/95gmol-1
3.315 moles of MgCl2
4 0
3 years ago
Read 2 more answers
Select the correct answer.
natali 33 [55]

The wave speed completely depends on the characteristics and properties of the medium  . . . physical properties for mechanical waves, electrical properties for electromagnedtic waves.

So if you want to change the speed of a wave, you have to change the medium . . . shoot it through some different kind of stuff. <em>(B) </em>

4 0
3 years ago
Read 2 more answers
Cual es la rapidez media de un guepardo que recorre 100 metros en 4 segundos? ¿Y si recorre 50 m en 2 s?
Maru [420]

Answer:

La rapidez media es 25 m/s en ambos casos.

Explanation:

Podemos definir como rapidez media al cociente entre la distancia total recorrida y el tiempo que se tardó en recorrer dicha distancia.

Así tenemos:

Rapidez media = Distancia/tiempo.

Entonces si el guepardo recorre 100m en 4 segundos, su rapidez media es:

Rapidez media = 100m/4s = 25 m/s

En el caso de que el guepardo recorre 50 metros en 2 segundos, su rapidez media será:

rapidez media = 50m/2s = 25m/s

Es el mismo resultado, pues recorrió la mitad de distancia en la mitad de tiempo.

4 0
3 years ago
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