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3 years ago

Question 10(Multiple Choice Worth 2 points)

Physics

2 answers:

Sunny_sXe [5.5K]3 years ago

4 0

D. 0.05 kg•m/s

Just multiply the two numbers :)

Please mark brainliest!

Svetach [21]3 years ago

3 0

$P = mv$

P momentum
m mass
v velocity

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HELP ME PLEASEEEEEEEEEEEEEE

ozzi

Answer: The correct statements are:

The atoms are very attracted to one another.
The atoms are held tightly together.

Explanation:

Solid state: In this state, the molecules are closely packed and cannot move freely from one place to another that means no space between them and the intermolecular force of attraction between the molecules are strong.

In solid substance, the particles are very close to each other due to this the intermolecular forces of attraction are strongest.

The key point about solid are:

The atoms are very attracted to one another.
The atoms are not moving freely.
It will not spread out evenly to fill any container.
The atoms are held tightly together.
The forces of attraction are strong to bring molecules together.
The atoms are close and in fixed positions.

7 0

3 years ago

Refraction is the bending of a wave disturbance as it passes at an angle from one ____ into another.

levacccp [35]

Refraction is the bending of a wave disturbance as it passes at an angle from one medium into another

3 0

4 years ago

"the velocity of the block is constant, so the net force acting on the block must be zero. Thus the normal force equals the weig

RSB [31]

Answer:

Explanation:

"the velocity of the block is constant, so the net force acting on the block must be zero. Thus the normal force equals the weight and the force of friction equals the applied force" The only thing which is wrongly stated here is that the normal force equals the weight. Normal force is not always equal to weight. If external force is applied at some angle with the horizon , normal force may be more or less than weight. Even in case of an object placed on an inclined plane , weight is not equal to normal force .

All other parts of the statement are correct.

6 0

3 years ago

A particle moves according to a law of motion s = f(t), t ≥ 0, where t is measured in seconds and s in feet. f(t) = 0.01t4 − 0.0

ivolga24 [154]

Since you solved a and b I will start with part c.
Part C
To answer this question we need to find zeros of a velocity function:
$v(t)=0.04t^3-0.06t^2$
We can factor this polynomial:
$v(t)=0.04t^3-0.06t^2=t^2(0.04t-0.06)$
Now it's pretty easy to find zeros. This function will be equal to zero when any of the factors are equal zero.
$t^2=0;\\ 0.04t-0.06=0$
We solve these two equations and we get our zeros:
$t_1=0; t_2=\frac{3}{2}$
The particle is at rest at t=0 and t=3/2.
Part D
To solve this we need to determine when our velocity function is greater than zero. We will use factored form.
We determine when each factor is greater than zero and with that information, we build the following table:
$\centering \label{my-label} \begin{tabular}{lllll} Range & -\infty & 0 & 3/2 & +\infty \\ t^2 & - & + & + & + \\ 0.04t-0.06 & - & - & + & + \\ t^2 (0.04t-0.06) & + & - & + & + \end{tabular}$
We can see, from the table, that our function is positive when $- \infty < t$ and t>3/2.
That is the range in which particle is moving in positive direction.
Part E
We know that distance traveled is given with:
$s(t)=0.01t^4 - 0.02t^3$
We simply plug in t=12 to find total distance traveled:
$s(12)=0.01(12)^4 - 0.02(12)^3=172.80 ft$
Part F
We know that acceleration is defined as a rate of change of velocity.
We find acceleration by taking the first derivative of velocity with respect to time.
$a(t)=\frac{dv}{dt}=(0.04t^3-0.06t^2)'=0.12t^2-0.12t$
To find acceleration after 1 second we simply plug in t=1s in above equation:
$a(1)=0.12-0.12=0$

7 0

4 years ago

Help me Plz this is due in 10 mins

mezya [45]

I think it's the first one

5 0

3 years ago