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Rudiy27
4 years ago
10

A sample of a substance that has a density of 0.844 g/mL has a mass of 0.549 g. Calculate the volume of the sample.

Chemistry
1 answer:
Virty [35]4 years ago
7 0
D = m / V

0.844 = 0.549 / V

V = 0.549 / 0.844

V = 0.650 mL


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Which equation represents a fission reaction? Superscript 14 subscript 7 upper N plus superscript 1 subscript 1 upper H right ar
soldi70 [24.7K]

Answer:

Superscript 235 subscript 92 upper U plus superscript 1 subscript 0 n right arrow superscript 140 subscript 55 upper C s plus superscript 94 subscript 37 upper R b plus 2 superscript 1 subscript 0 n

Explanation:

Nuclear fission is a nuclear reaction in which the nucleus of an atom splits into smaller parts (lighter nuclei). The fission process often produces free neutrons and releases a large amount of energy,for example, uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. The fission of heavy elements is an exothermic reaction, and huge amounts of energy are released in the process.

If we look at the equation given in the answer, we will notice that a uranium-235 nucleus was bombarded with neutrons and it split into caesium-140, Rubidium-94 and more neutrons. This process takes place in nuclear reactors and is a self-sustaining process. It is self sustaining be cause more neutrons are produced, thereby continuing the fission reaction.

8 0
3 years ago
How much heat is required to take a 150 g sample of water from 10.0 ℃ to 95.0 ℃? cs,water = 4.184 J/g*℃
Setler79 [48]

Answer:

\boxed {\boxed {\sf 53, 346 \ Joules}}

Explanation:

We are given the specific heat and change in temperature, so we should use this heat formula:

q=m C \Delta T

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We know the mass is 150 grams. The specific heat of water is 4.184 J/g °C.

Let's find the change in temperature.

Subtract the initial temperature from the final temperature.

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  • ΔT= 95.0 °C - 10.0 °C= 85.0 °C

Now we know all the values:

m= 150 \ g \\C= 4.184 J/ g \  \textdegree C \\\Delta T= 85.0 \textdegree C

Substitute them into the formula.

q=(150 \ g) (4.184 \ J/g \ \textdegree C)(85.0 \textdegree C )

Multiply all three numbers together. Note that the grams (g) and degrees Celsius (°C) will cancel out. Joules (J) will be the only remaining unit.

q=(627.6 \ J/ \textdegree C) ( 85.0 \textdegree C)

q=53346 \ J

<u>53,346 Joules</u> of heat are required.

4 0
3 years ago
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Answer:

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Explanation:

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Answer:

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