117.22 g are needed to react with an excess of Fe2O3 to produce 156.2 g of Fe.
Explanation:
Moles of Fe = Mass of Fe in grams / Atomic weight of Fe
= 156.2 / 55.847
Moles of Fe = 2.79.
The ratio between CO and Fe id 3 : 2.
Moles CO needed = 2.79 * (3 / 2)
= 4.185.
To calculate Atomic weight of CO,
Atomic weight of carbon = 12.011
Atomic weight of oxygen= 15.9994
Atomic weight of CO = 12.011 + 15.9994 = 28.01 g / mol.
Mass of CO = 4.185 * 28.01 = 117.22 g.
I believe it is B. A series circuit has one path for electrons, but a parallel circuit has more then one path.
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M=f/a m=129000N/84m/s/s=1535.714286kg/m/s/s
Answer:
The mass of CH4 is 60, 29 grams.
Explanation:
We use the weight of the atoms C and H for calculate the molar mass:
Weight of CH4= weight C+ 4 x weight H= 12,01 g/mol +4 x 1,008g/mol=
Weight of CH4 =16, 042 g/mol
1molCH4-----16, 042grams
3,758 mol CH4--X= (3,758 mol CH4 x 16, 042 grams)/1 mol CH4=60,285836 grams
