Answer:
The maximum height of the ball is 2 m.
Explanation:
Given that,
Mass of ball = 50 g
Height = 1.0 m
Angle = 30°
The equation is
We need to calculate the velocity
Using conservation of energy
Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero
Put the value into the formula
Put the value into the formula
We need to calculate the maximum height of the ball
Using again conservation of energy
Here, h = y highest point
Put the value into the formula
Put the value of y in the given equation
Hence, The maximum height of the ball is 2 m.
The slope of the line on a velocityversus time graph is equal to the acceleration of the object. If the object is moving with an acceleration of +4 m/s/s (i.e., changing its velocity by 4 m/s per second), then the slope of the line will be +4 m/s/s.
Electrical current is measured using the ampere.
Using the average velocity formula which is total distance divided by total time. If the distance is given in km convert to m then divide by 1000 to get m and if time is given in minutes then divide by 60 to get seconds. And after converting, divide to get your final answer in m/s. Hope that helped!
Potential energy =
(mass) x (gravity) x (height above the reference level) .
Relative to the bottom of the cliff, the potential energy
at the top of the cliff is
(25kg) x (9.8 m/s²) x (30 meters)
= (25 x 9.8 x 30) kg-m²/s²
= 7,350 joules .
Kinetic energy = (1/2) x (mass) x (speed²)
The rock's kinetic energy at the bottom is
the same as its potential energy at the top.
7,350 joules = (1/2) x (25 kg) x (speed²)
Divide each side
by 12.5kg : 7,350 joules/12.5 kg = speed²
7,350 kg-m²/s² / 12.5kg = speed²
(7,350 / 12.5) m²/s² = speed²
588 m²/s² = speed²
Take the square root
of each side:
Speed = √(588 m²/s²)
= 24.248... m/s (rounded)
