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Vinvika [58]
3 years ago
7

An ac series circuit contains a 20 ohm resistor, a capacitor of 0.75 micro farad, and an inductor of 120 mH. What frequency shou

ld be used to create a resonance condition
Physics
1 answer:
Blababa [14]3 years ago
5 0

Answer:

530.5 Hz

Explanation:

Given :

C=0.75 micro

L=120 mH

Reactance capacitor can be determined by

=\frac{1}{ wC}

where c =capacitor

= \frac{1}{w*0.75*10^-6}

Reactance inductor can be determined by

= w*L\\ = w*120*10^-3

As they are in series so ,

\frac{1}{w*0.75*10^-6}  =w*120*10^-3

On solving these value we get

w=3333.33

As we know that

f = \frac{w}{2*3.14} =

530.5 Hz

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