Question

Calculate the mass in grams of a sample of Americium containing six atoms

Answer 1

Americium has a molar mass of 243 g/mol.
There are 6.022*10^23 atoms in a mol (Avogadro's number).

6 atoms / 6.022 * 10^23 atoms/mol gives us:

9.963*10^-24 mols

Lastly: 9.963*10^-24 mols * 243 g/mol = 2.42*10^-21 g

Answer 2

Answer: $243\times 10^{-23}$  grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles. and weighs equal to the molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given atoms}}{\text {Avogadro's number}}=\frac{6}{6.023\times 10^{23}}=1.0\times 10^{-23}moles$

1 mole of Americium weighs = 243 g

Thus $1.0\times 10^{-23}moles$ of Americium weigh=$\frac{243}{1}\times 1.0\times 10^{-23}=243\times 10^{-23}g$

Thus the mass  mass in grams of a sample of Americium containing six atoms is $243\times 10^{-23}$