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sashaice [31]
3 years ago
6

Nellie newton swings a rock into a circular path while holding an attached string overhead. the string makes a 45-degree angle t

o the vertical (comprising a "conical pendulum"). the centripetal force that holds the rock in its circular path is the
Physics
1 answer:
taurus [48]3 years ago
6 0
Horizontal component of the string tension
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Scenario 2: Use the following information to answer questions 3 and 4:
NemiM [27]

Answer:

A. 52 min

.A. 47 watts

Explanation:

Given that;

jim weighs 75 kg

and he walks 3.3 mph; the objective here is to determine how long must he walk to expend 300 kcal.

Using the following relation to determine the amount of calories burned per minute while walking; we have:

\dfrac{MET*weight (kg)*3.5}{200}

here;

MET = energy cost of a physical activity for a period of time

Obtaining the data for walking with a speed of 3.3 mph From the  standard chart for MET, At 3.3 mph; we have our desired value to be 4.3

However;

the calories burned in a minute = \dfrac{4.3*75 (kg)*3.5}{200}

= 5.644

Therefore, for walking for 52 mins; Jim  burns approximately 293.475 kcal which is nearest to 300 kcal.

4.

Given that:

mass m = 75 kg

intensity = 6 kcal/min

The eg ergometer work rate = ??

Applying the formula:

V_O_2 ( intensity ) = ( \dfrac{W}{m}*1.8)+7

where ;

V_O_2 ( intensity ) = \dfrac{1 \ kcal min^{-1}*10^{-3}}{5}

V_O_2 ( intensity ) = \dfrac{6*1 \ kcal min^{-1}*10^{-3}}{5}

V_O_2 ( intensity ) = 0.0012

∴0.0012 = (\dfrac{W}{75}*1.8)+7 \\ \\ W = \dfrac{0.0012-7}{1.8}*75 \\ \\ W = \dfrac{7*75}{1.8}  \\ \\ W = 291.66 \ kg m /min

Converting to watts;

Since;  6.118kg-m/min is =  1 watt

Then 291.66 kgm /min will be equal to 47.67 watts

≅ 47 watts

3 0
4 years ago
A certain unbalanced force gives a 5kg object an acceleration of 15 m/s2. What would be the acceleration if the same force was a
stira [4]

Answer:

a2 = 2.5 m/s2

Explanation:

F1 = m1 a1 We use the same force so F1 = F2

= 5kg × 15m/s2 F2 = m2 a2

= 75N a2 is required

a2 = F2 / m2

= 75N / 30 kg

= 2.5 m/s2

7 0
4 years ago
What is the atmosphere of Ganymede made up of?
Arada [10]

Answer:

Oxygen Atmosphere

Explanation:

5 0
4 years ago
A simple series circuit consists of a 130 ? resistor, a 30.0V battery, a switch, and a 2.10 pF parallel-plate capacitor (initial
V125BC [204]

Answer with Explanation:

We are given that

Resistance,R=130 ohm

Potential difference, V=30 V

Capacitor,C=2.1pF=2.1\times 10^{-12} F

1pF=10^{-12} F

d=5.0 mm=5\times 10^{-3} m

1mm=10^{-3} m

a.Maximum flux

\phi=EA=\frac{V}{d}\times \frac{Cd}\epsilon_0}=\frac{CV}{\epsilon_0}

\epsilon_0=8.85\times 10^{-12}

\phi=\frac{2.1\times 10^{-12}\times 30}{8.85\times 10^{-12}}=7.12Vm

b.Maximum displacement current,I=\frac{V}{R}=\frac{30}{130}=0.23 A

c.We have to find electric flux at t=0.5 ns

t=0.5ns=0.5\times 10^{-9} s

1ns=10^{-9}s

q=CV(1-e^{-\frac{t}{RC}})

q=30\times 2.1\times 10^{-12}(1-e^{-\frac{0.5\times 10^{-9}}{130\times 2.1\times 10^{-9}})

q=52.9\times 10^{-12} C

\phi=\frac{q}{\epsilon_0}=\frac{52.9\times 10^{-12}}{8.85\times 10^{-12}}=5.98Vm

d.Displacement current at t=0.5ns

I=(\frac{V}{R})e^{-\frac{t}{RC}}=\frac{30}{130}e^{-\frac{0.5\times 10^{-9}}{130\times 2.1\times 10^{-12}}}

I=0.037 A

5 0
3 years ago
What affect does doubling the net force have on the acceleration of the object (when
Triss [41]
<h3>Answer: The acceleration doubles</h3>

===========================================================

Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

---------------

Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

---------------

In summary, if you double the net force applied to the object, then the acceleration doubles as well.

8 0
3 years ago
Read 2 more answers
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