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alexira [117]
3 years ago
12

Kai was 200 meters north of the library when he remembered he had to return some books to the library. It took him 200 seconds t

o do the round trip.
Answer
His speed was 2 m/s, and his velocity was 0.
Physics
2 answers:
sineoko [7]3 years ago
7 0

Answer:

B his speed was 2 m/s, and his velocity was 0

Explanation:

IRINA_888 [86]3 years ago
4 0

Kai was 200 meters north of the library when he remembered he had to return some books to the library. It took him 200 seconds to do the round trip.

Answer

His speed was 2 m/s, and his velocity was 0.

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Answer:

3.25 × 10^7 m/s

Explanation:

Assuming the electrons start from rest, their final kinetic energy is equal to the electric potential energy lost while moving through the potential difference (ΔV)

Ek = 1/2 mv2 = qΔV .................. 1

Given that V is the electron speed in m/s

Charge of electron = 1.60217662 × 10-19 coulombs

Mass of electron = 9.109×10−31 kilograms

ΔV = 3.0kV = 3000V

Make V the subject of the formula in eqaution 1

V = sqr root 2qΔV/m

V = 2 × 1.60217662 × 10-19 × 3000 / 9.109×10−31

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3 0
3 years ago
The speed of light in a transparent medium is 0.6 times that of its speed in vacuum. Find the refractive index of the medium.
grin007 [14]
<h2>Answer:</h2>

The refractive index is 1.66

<h2>Explanation:</h2>

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So

RI = 1/0.6 = 5/3 or 1.66

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