Answer:
work done is -150 kJ
Explanation:
given data
volume v1 = 2 m³
pressure p1 = 100 kPa
pressure p2 = 200 kPa
internal energy = 10 kJ
heat is transferred = 150 kJ
solution
we know from 1st law of thermodynamic is
Q = du +W ............1
put here value and we get
-140 = 10 + W
W = -150 kJ
as here work done is -ve so we can say work is being done on system
D, all notebooks would hit the floor at the same time. The time it takes to hit the floor is independent of their weight, but rather dependent on the acceleration of gravity. Since gravity is constant, they will all hit the floor at the same time.
His position x = V* t = 6.7*56= 375.2 m from point a
The Young modulus E is given by:

where
F is the force applied
A is the cross-sectional area perpendicular to the force applied

is the initial length of the object

is the increase (or decrease) in length of the object.
In our problem,

is the initial length of the column,

is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:

and the cross-sectional area is

The force applied to the column is the weight of the load:

Now we have everything to calculate the compression of the column:

So, the column compresses by 1.83 millimeters.
Answer:

Explanation:
If we express all of the cordinates in their rectangular form we get:
A = (1404.77 , 655.06) m


Since we need C to be (0,0) we stablish that:

That way we make an equation system from both X and Y coordinates:


Replacing values:
With this system we can solve for both Db and Dc and get the answers to the question:

