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Natali [406]
3 years ago
8

Which of the following pairs of aqueous solutions will form a precipitate when mixed?

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

The correct answer is A) Pb(C₂H₃O₂)₂ + Li₂SO₄

Explanation:

  • All salts of Na, K and ammonium are soluble.
  • All nitrates are soluble.
  • All chlorides are soluble, with the exception of AgCl, Hg₂Cl₂, PbCl₂ and CuCl.
  • All sulfates are soluble, with the exception of CaSO₄, SrSO₄, BaSO₄, PbSO₄, HgSO₄, Hg₂SO₄ and Ag₂SO₄.
  • All hydroxides are poorly soluble, with the exception of alkaline hydroxides, Sr(OH)₂, Ba(OH)₂ and NH4(OH)
  • All carbonates are poorly soluble, with the exception of alkaline carbonates and ammonium carbonate.
  • All sulfides are poorly soluble, with the exception of alkaline sulfides, alkaline earth sulfides, and ammonium sulfide.

The reaction A is:

Pb(C₂H₃O₂)₂ + Li₂SO₄ ⇒PbSO₄ + 2 LiC₂H₃O₂

Lead sulfate is a slightly soluble solid, therefore it precipitates.

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What type of change is this picture showing?
sladkih [1.3K]

Answer: physical

Explanation: freezing and melting are physical changes.

8 0
2 years ago
Suppose it took 108 joules of energy to raise a bar of gold from 25 °C to 29.7°C. Given that the specific heat capacity of gold
Lady bird [3.3K]

Answer:

m = 180 g

Explanation:

Given data:

Energy absorbed = 108 J

Mas of gold = ?

Initial temperature = 25°C

Final temperature = 29.7 °C

Specific heat capacity of gold = 0.128 J/g.°C

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =29.7 °C - 25°C

ΔT = 4.7 °C

108 J = m ×0.128 J/g.°C ×4.7 °C

108 J = m ×0.60 J/g

m = 108 J/0.60 J/g

m = 180 g

3 0
3 years ago
A sample of helium gas in a balloon is compressed from 4.0 L to 3.2 L at a constant temperature. If the pressure of the gas in t
vampirchik [111]

Answer:

286 kPa

Explanation:

Boyles law states that volume of gas is inversely proportional to pressure o gas for a fixed amount of gas at constant temperature

P1V1 = P2V2

where P1 is pressure and V1 is volume at first instance

P2 is pressure and V2 is volume at the second instance

substituting the values in the equation

229 kPa x 4.0 L = P2 x 3.2 L

P2 = 286.25 kPa

the new pressure is 286 kPa

4 0
3 years ago
Huge loops of plasma erupting from the sun are called.
olasank [31]

Answer:

magnetic Flux ropes

Explanation:

Magnetic flux ropes (also known as coronal loops and solar prominences) sit on the surface of the sun, with matter and energy flowing through them, for hours or days.

5 0
2 years ago
you wish to make a 0.161 m hydroiodic acid solution from a stock solution of 3.00 m hydroiodic acid. how much concentrated acid
mestny [16]

5.367 ml of the concentrated acid must be added to obtain a total volume of 100 ml of the dilute solution.

Dilution is defined as the process in which the concentration of a sample is decreased by adding more solvent. The dilution formula is given below.

C₁V₁ = C₂V₂

where C₁ = initial concentration of sample = 3.00 m

V₁ = initial volume of sample

C₂ = final concentration after dilution = 0.161 m

V₂ = total final volume after dilution = 100 ml

Plug in the values to the formula and solve for the volume of the concentrated acid that must be added.

C₁V₁ = C₂V₂

3.00 m (V₁) = 0.161 m (100 ml)

V₁ = 5.367 ml

Learn more about dilution here: brainly.com/question/1615979

#SPJ4

3 0
1 year ago
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