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3 years ago

F Penny's piston is wider than Pauly's, who is pushing with greater force?

2 answers:

8 0

A Penny is exerting the greater force.
B Pauly is exerting the greater force.
C They are both using equal force.
Think its A or C

Yuliya22 [10]3 years ago

7 0

It would depend on who is stronger but it is likely that Penny would be creating larger pressure because the surface area is less. If this is part of a question where the pressure for both is the same then Pauly is pushing with greater force, I know this because force/area=pressure and when the surface area is larger the force must be greater as well.

Hope this helps :)

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Can u Anwser this Plzzzz

nata0808 [166]

Answer:

-0. 75m/s^2

Explanation:

use formula of acceleration

5 0

3 years ago

Is it possible to have a net torque when all of the forces sum to zero? Explain.

nexus9112 [7]

Answer:

Yes it is possible

Explanation:

When two equal magnitude forces are acting on the rod in opposite direction

Then the net force on the system is always zero in that case

so we will have

$F - F = 0$

now for the system net torque due to these forces is given by

$\tau = F(r_1) + F(r_2)$

here we know that

$r_1, r_2$ = distance of the forces from reference about which torque is measured

so here we can say that net force is zero on the system while torque is not zero

in all such case object will rotate about a fixed position with change angular speed

3 0

3 years ago

The loaded cab of an elevator has a mass of 3.0 x 10 3 kg and moves 200 m up the shaft in 20 s at constant speed. At what averag

Alexeev081 [22]

The average rate at which the cable does work is 294,000 J/s.

The given parameters:

mass, m = 3000 kg
height, h = 200 m
time of motion, t = 20 s

The average rate at which the cable does work is calculated as follows;

$P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{3000 \times 9.8 \times 200}{20} \\\\P = 294,000 \ J/s$

Thus, the average rate at which the cable does work is 294,000 J/s.

Learn more about energy and power here: brainly.com/question/13387946

4 0

3 years ago

A monatomic gas is adiabatically compressed to 0.250 of its initial volume. Do each of the following quantities change?

Len [333]

Answer:

Given that

V2/V1= 0.25

And we know that in adiabatic process

TV^န-1= constant

T1/T2=( V1 /V2)^ န-1

So = ( 1/0.25)^ 0.66= 2.5

Also PV^န= constant

So P1/P2= (V2/V1)^န

= (1/0.25)^1.66 = 9.98

A. RMS speed is

Vrms= √ 3RT/M

But this is also

Vrms 2/Vrms1= (√T2/T1)

Vrms2=√2.5= 1.6vrms1

Lambda=V/4π√2πr²N

Lambda 2/lambda 1= V2/V1 = 0.25

So the mean free path can be inferred to be 0.25 times the first mean free path

C. Using

Eth= 3/2KT

So Eth2/Eth1= T2/T1

Eth2= 2.5Eth1

Using CV= 3/2R

Cvf= Cvi

So molar specific heat constant does not change

5 0

3 years ago

Read 2 more answers

A flat coil having 160 turns, each with an area of 0.20 m 2, is placed with the plane of its area perpendicular to a magnetic fi

S_A_V [24]

Answer:

10.2 Watt

Explanation:

$N$ = number of turns in flat coil = 160

$A$ = area = 0.20 m²

B₀= initial magnetic field = 0.40 T

$B$ = final magnetic field = - 0.40 T

Change in magnetic field is given as

ΔB = B - B₀ = - 0.40 - 0.40 = - 0.80 T

$t$ = time taken for the magnetic field to change = 2.0 s

Induced emf is given as

$E = \frac{- N A \Delta B}{t}$

$E = \frac{- (160) (0.20) (- 0.80)}{2}$

$E$ = 12.8 volts

$R$ = Resistance of the coil = 16 Ω

Power is given as

$P = \frac{E^{2}}{R}$

$P = \frac{(12.8)^{2}}{16}$

$P$ = 10.2 Watt

6 0

3 years ago