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Ket [755]
3 years ago
6

What type of clouds usually accompany cold fronts?

Physics
2 answers:
ASHA 777 [7]3 years ago
6 0

Answer: Cumulus

Explanation: Most large cloud fronts are made up of cumulus clouds, large storm clouds are cumulonimbus clouds.

alina1380 [7]3 years ago
4 0
The correct answer is A

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An object is attached to a vertical spring and bobs up and down between points A and B. Where is the object located when its kin
gtnhenbr [62]

Answer:

a. at either A or B

Explanation:

Kinetic energy may be defined as the energy of the system or an object which is due to its velocity of the object it possess.

In the context, an object having mass  is attached to spring which is vertical and the object moves up and down due to spring effect between points A and B. Now these points A and B are the extreme points after which the object bounces back.

At point A and B, the velocity of the object becomes zero and hence the kinetic energy of a body varies directly proportional to its velocity.

                  i.e. Kinetic energy $= \frac{1}{2} \text{mass} \times (\text{ velocity})^2$  

4 0
3 years ago
PLS HELP Do you believe this relationship between incident and reflected angles would occur even if the medium interface were cu
Anna35 [415]
The Law of reflection would still hold even off a curved surface. Since the angles are measured from the normal, which is perpendicular to the surface, curved surfaces don't matter. This is basis of curved mirrors such as concave and convex 
4 0
3 years ago
The scientific unit used to measure distance is the?
alexgriva [62]

Answer:

Meter.

Explanation:

4 0
3 years ago
A charge of 0.14 C is moved from a position where the electric potential is 20 V to a position where the electric potential is 5
alukav5142 [94]

The change in electric potential energy is given by:

ΔU = ΔVq

ΔU = change in PE, ΔV = potential difference, q = charge

Given values:

ΔV = 50V - 20V = 30V, q = 0.14C

Plug in and solve for ΔU:

ΔU = 30(0.14)

ΔU = 4.2J

7 0
2 years ago
A bullet is shot vertically upward with an initial velocity of 128 ft/s. The bullet's height after t seconds is y(t) = 128t - 16
saul85 [17]

The height of the bullet when the velocity is zero is 256 ft.

<h3>Height of the bullet when the velocity is zero </h3>

The height of the bullet when the velocity is zero is determined by taking derivative of the function as shown below;

v = \frac{dy}{dt} = 128 -32t \\\\when \ v \ is \ zero\\\\v = 0\\\\128 - 32t = 0\\\\32t = 128\\\\t = \frac{128}{32} \\\\t = 4 \  s

The height of the bullet at this time is calculated as follows;

y(4) = 128(4) - 16(4)^2\\\\y(4) = 256 \ ft

Learn more about height of projectiles here: brainly.com/question/10008919

6 0
2 years ago
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