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nalin [4]
4 years ago
14

When a gas is cooled, the particles begin to move more______(Quickly/slowly). When the temperature drops below the____ (melting

point/boiling point), the substance's particles have condensed and formed a liquid. If the liquid is cooled down even more, the amount of thermal energy in the particles will____(increase/decrease), and the liquid's temperature will continue to decrease. Eventually, the substance will freeze and form a solid. If the temperature continues to
(Increase/decrease), the particles in the solid will____ (Vibrate in place/move around one another) more slowly.
Physics
1 answer:
bija089 [108]4 years ago
6 0
Slowly; Boiling Point; Decrease; Decrease; Vibrate in place.

As temperature drops, so does thermal energy, and particle motion drops. The same trends in temperature, thermal energy, and motion applys to phases in decreasing order: gas>liquid>solid. The particle motion is always vibrations in place for solids because they are very tightly packed compared to liquids and gases.
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Answer:

\vec{F}=0.40176 N \hat{k}

Explanation:

To calculate the force we need to use this equation

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\vec{B} = B \hat{j} = 0.62\hat{j} [ T]

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\vec{dl}\times\vec{B}=dx \hat{i}\times B \hat{j} = Bdx\hat{k}

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F = \int\limits^L_0 {i(\vec{dl}\times\vec{B})}=\int\limits^L_0{iBdx\hat{k}}

So here we use the fact that B=0 in any point of the x axis that is not x^{'}=0.27 [m], that means that we only need to do the integration between a very short distant behind the point x^{'}=0.27 [m] and a very short distant after that point, meaning:

\vec{F}= \lim_{h \to 0}{\int\limits^{x^{'}+h}_{x^{'}-h}{iBdx\hat{k}} }

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2,4*0,62*2,7 ( \frac{ kgm }{ s^{2} } ) \hat{k}

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3 years ago
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Explanation:

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