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nalin [4]
3 years ago
14

When a gas is cooled, the particles begin to move more______(Quickly/slowly). When the temperature drops below the____ (melting

point/boiling point), the substance's particles have condensed and formed a liquid. If the liquid is cooled down even more, the amount of thermal energy in the particles will____(increase/decrease), and the liquid's temperature will continue to decrease. Eventually, the substance will freeze and form a solid. If the temperature continues to
(Increase/decrease), the particles in the solid will____ (Vibrate in place/move around one another) more slowly.
Physics
1 answer:
bija089 [108]3 years ago
6 0
Slowly; Boiling Point; Decrease; Decrease; Vibrate in place.

As temperature drops, so does thermal energy, and particle motion drops. The same trends in temperature, thermal energy, and motion applys to phases in decreasing order: gas>liquid>solid. The particle motion is always vibrations in place for solids because they are very tightly packed compared to liquids and gases.
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Wittaler [7]
Kinetic energy is energy that is in motion, thats all I remember
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3 years ago
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A woman can row her canoe at 2.5 m/s. If she faces an opposing current of 3.0 m/s, how fast will she go forward?
taurus [48]

Answer:

V = - 0.5 [m/s]

Explanation:

In order to solve this problem, we must use the principle of relative speeds. This is for an observer who is on the edge of the river he can see how the river moves to the left and the woman tries to move to the right but can not since:

V_{total}=-3+2.5\\V_{total}=-0.5 [m/s]

That is, the person sees how the woman moves to the left but with avelocity of 0.5 [m/s] to the left

8 0
2 years ago
A train traveling at 25 m/s is blowing its whistle at 440 Hz as it crosses a level crossing. You are waiting at the crossing and
ohaa [14]

Answer:

b) 472HZ, 408HZ

Explanation:

To find the frequencies perceived when the bus approaches and the train departs, you use the Doppler's effect formula for both cases:

f_o=f\frac{v_s+v_o}{v_s-v}\\\\f_o=f'\frac{v_s-v_o}{v_s+v}\\\\

fo: frequency of the source = 440Hz

vs: speed of sound = 343m/s

vo: speed of the observer = 0m/s (at rest)

v: sped of the train

f: frequency perceived when the train leaves us.

f': frequency when the train is getTing closer.

Thus, by doing f and f' the subjects of the formulas and replacing the values of v, vo, vs and fo you obtain:

f=f_o\frac{v_s-v}{v_s+v_o}=(440Hz)\frac{340m/s-25m/s}{340m/s}=408Hz\\\\f'=f_o\frac{v_s+v}{v_s-v_o}=(440Hz)\frac{340m/s+25m/s}{340m/s}=472Hz

hence, the frequencies for before and after tha train has past are

b) 472HZ, 408HZ

6 0
3 years ago
An 8.0 cm object is 40.0 cm from a concave mirror that has a focal length of 10.0 cm. Its image is 16.0 cm in front of the mirro
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Now that we have the value of p, we can plug it into the magnification equation.

M=-16/13.33=1.2
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So the height of the image produced by the mirror is 9.6cm.
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