Answer:
The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s
Explanation:
From Newton's second law, F = mg and also from coulomb's law F= Eq
Dividing both equations by mass;
F/m = Eq/m = mg/m, then
g = Eq/m --------equation 1
Again, in a projectile motion, the time of flight (T) is given as
T = (2usinθ/g) ---------equation 2
Substitute in the value of g into equation 2

Charge of proton = 1.6 X 10⁻¹⁹ C
Mass of proton = 1.67 X 10⁻²⁷ kg
E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°
Solving for T;

T = 7.83 X10⁻⁷ s
Answer:
- 5436 J
Explanation:
mass of car, m = 120 kg
radius of loop, r = 12 m
velocity at the bottom (A) = Va = 25 m/s
Velocity at the top(B) = Vb = 8 m/s
Vertical distance from A to B = diameter of loop, h = 2 x 12 = 24 m
by use of Work energy theorem
Work done by all the forces = change in kinetic energy of the body
Work done by the force + Work done by the friction = Kinetic energy at B - kinetic energy at A
- m x g x h + Work done by friction = 0.5 x 120 x (Vb^2 - Va^2)
- 120 x 9.8 x 24 + Work done by friction = 60 x (64 - 625)
- 28224 + Work done by friction = - 33660
Work done by friction = -33660 + 28224 = - 5436 J
Answer:
Option B
Technician B only is correct
Explanation:
Technician a is wrong because the rupture was not caused by switching DOT (Department of Transportation) 3 and DOT 4 Brake fluids. As a matter of fact both brake fluids are compatible with most vehicular systems, and to a certain extent they can be used interchangeably without any adverse effect.
Technician B on the other hand, gives a more accurate reason, since a twisted brake hose will definitely fail and rupture once enough force is applied to it, which is most likely the case of what happened considering the mileage it ran before rupturing. Within this mileage, it is very possible for the pressure on the already twisted brake hose to have been damaging it gradually before finally making it to rupture.
The answer would be that they are close to water hope this helps!
Answer:
3+2i ohm.
Explanation:
Here we have a complex number operation. According to Ohm's law V=I*R, so:

we need to remove the complex number on the denominator, so we have to multiply by its complement on both side

that gives us:
