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HACTEHA [7]
3 years ago
15

A Ferris wheel has radius 4.0 m and makes one revolution every 30 s with uniform rotation. A woman who normally weighs 600 N is

sitting on one of the benches attached at the rim of the wheel. What is her apparent weight (the normal force exerted on her by the bench) as she passes over the top of the Ferris wheel? A. 590 N
B. 600 N
C. 520 N
D. 0 N
Physics
1 answer:
sasho [114]3 years ago
6 0

Answer:

A) Apparent Weight = 590 N

Explanation:

As we know that frequency is given as

f = \frac{1}{30}

f = 0.033 Hz

now the angular speed is given as

\omega = 2\pi f

\omega = 2\pi(0.033) = 0.21 rad/s

now at the top position we will have

mg - N = m\omega^2 R

N = mg - m\omega^2 R

N = 600 - \frac{600}{9.8}(0.21)^2(4.0)

N = 590 N

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A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a
GuDViN [60]

Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

Explanation:

From Newton's second law, F = mg and also from coulomb's law F= Eq

Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1

Again, in a projectile motion, the time of flight (T) is given as

T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}

Charge of proton = 1.6 X 10⁻¹⁹ C

Mass of proton = 1.67 X 10⁻²⁷ kg

E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°

Solving for T;

T = \frac{(1.67X10^{-27}* 2*3X10^4sin 30}{400*1.6X10^{-19}}

T = 7.83 X10⁻⁷ s

6 0
3 years ago
You are testing a new amusement park roller coaster with an empty car with a mass 120 kg. One part of the track is a vertical lo
Kay [80]

Answer:

- 5436 J

Explanation:

mass of car, m = 120 kg

radius of loop, r = 12 m

velocity at the bottom (A) = Va = 25 m/s

Velocity at the top(B) = Vb = 8 m/s

Vertical distance from A to B = diameter of loop, h = 2 x 12 = 24 m

by use of Work energy theorem

Work done by all the forces = change in kinetic energy of the body

Work done by the force + Work done by the friction = Kinetic energy at B - kinetic energy at A

- m x g x h + Work done by friction = 0.5 x 120 x (Vb^2 - Va^2)

- 120 x 9.8 x 24 + Work done by friction = 60 x (64 - 625)

- 28224 + Work done by friction = - 33660

Work done by friction = -33660 + 28224 = - 5436 J

4 0
3 years ago
A technician is diagnosing a car that had both front brake hoses replaced 5,000 miles ago. An inspection reveals that the right
Mamont248 [21]

Answer:

Option B

Technician B only is correct

Explanation:

Technician a is wrong because the rupture was not caused by switching DOT (Department of Transportation) 3 and DOT 4 Brake fluids. As a matter of fact both brake fluids are compatible with most vehicular systems, and to a certain extent they can be used interchangeably without any adverse effect.

Technician B on the other hand, gives a more accurate reason, since a twisted brake hose will definitely fail and rupture once enough force is applied to it, which is most likely the case of what happened considering the mileage it ran before rupturing. Within this mileage, it is very possible for the pressure on the already twisted brake hose to have been damaging it gradually before finally making it to rupture.

4 0
3 years ago
NEED ANSWER FAST WILL GIVE BRAINLIEST ANSWER IF CORRECT.
Aleonysh [2.5K]
The answer would be that they are close to water hope this helps!
6 0
3 years ago
Read 2 more answers
In electronics, the formula V = IR is called Ohm's Law. It gives the relationship in a circuit between the voltage V (in volts),
Tomtit [17]

Answer:

3+2i ohm.

Explanation:

Here we have a complex number operation. According to Ohm's law V=I*R, so:

R=\frac{V}{I}\\\\R=\frac{21+i}{5-3i}

we need to remove the complex number on the denominator, so we have to multiply by its complement on both side

R=\frac{21+i}{5-3i}*\frac{5+3i}{5+3i}

that gives us:

R=\frac{102+68i}{34}=3+2i

6 0
4 years ago
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