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3 years ago

5

Determine the final temperature of a gold nugget (mass = 376 g) that starts at 398 K and loses 4.85 kJ of heat to a snowbank whe

n it is lost. The specific heat capacity of gold is 0.128 J/g°C.

1 answer:

m_a_m_a [10]3 years ago

6 0

Answer: Final temperature of a gold nugget will be 297 K

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$q=m\times c\times (T_{final}-T_{initial})$

q = heat released = -4.85 kJ = -4850 J

m = mass of metal = 376 g

$T_{final}$ = final temperature of metal = ?

$T_{initial}$ = initial temperature of metal = 398 K

c = specific heat of metal =

$-4850=376\times 0.128\times (T_{final}-398)$

$(T_{final}-398)=-101$

$(T_{final}=297K$

Thus the final temperature of a gold nugget will be 297 K

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given,

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b) When two person enters into the pool,

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$\rho \mathrm{Vg}=2 \mathrm{mg} \\$

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1 year ago

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3 years ago