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KengaRu [80]
3 years ago
5

Determine the final temperature of a gold nugget (mass = 376 g) that starts at 398 K and loses 4.85 kJ of heat to a snowbank whe

n it is lost. The specific heat capacity of gold is 0.128 J/g°C.
Physics
1 answer:
m_a_m_a [10]3 years ago
6 0

Answer: Final temperature of a gold nugget will be 297 K

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

q=m\times c\times (T_{final}-T_{initial})

q = heat released  = -4.85 kJ = -4850 J

m = mass of metal =  376 g

T_{final} = final temperature of metal = ?

T_{initial} = initial temperature of metal = 398 K

c = specific heat of metal =

-4850=376\times 0.128\times (T_{final}-398)

 (T_{final}-398)=-101

 (T_{final}=297K

Thus the final temperature of a gold nugget will be 297 K

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