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3 years ago

In order to design an experiment, you need a ____ about the scientific question you are trying to answer.

Physics

2 answers:

frez [133]3 years ago

8 0

In order to design an experiment, you need a hypothesis about the scientific question you are trying to answer.

goldenfox [79]3 years ago

6 0

In order to design an experiment, you need a hypothesis about the scientific question you are trying to answer.

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HELP - What are some good topics to add to a Pipeline presentation? So yes, a presentation about pipelines, like for example in

In-s [12.5K]

Talk about the jobs that pipeline construction provides to citizens and wether or not it’s effects are ultimately eco-friendly

6 0

3 years ago

Two spherical objects have masses of 6.2 x 105 kg and 13 x 103 kg. The gravitational attraction between them is 130 N. How far a

Neporo4naja [7]

Answer:

r = 6.4 cm

Explanation:

F = GMm/r²

r = √(GMm/F)

r = √((6.674e-11)(6.2e5)(13e3)/130)

r = 0.06432... m

Those are some high density materials!

8 0

2 years ago

For a movie stunt, an empty truck with a mass of 2000 kg goes 10 m/s and runs into a stopped car of mass 1000 kg. the truck then

babunello [35]

ANSWER

Both trucks will move together with speed v = 6.67 m/s

so correct answer will be

The speed of the combined vehicles is less than the initial speed of the truck.

EXPLANATION

As we know that there is no external force on the system of two trucks

So here momentum of the two trucks before collision and after collision will remain same

So here we will have

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

so here we will have

$v_{1i} = 10 m/s$

$v_{2i} = 0$

$m_1 = 2000 kg$

$m_2 = 1000 kg$

now we will have

$2000\times 10 + 1000\times 0 = (2000 + 1000) v$

$v = \frac{20000}{3000} = 6.67 m/s$

so correct answer will be

The speed of the combined vehicles is less than the initial speed of the truck.

3 0

2 years ago

Read 2 more answers

Two equal charges are 2m2m apart. If the charges and the distance are divided by two, how is the force between the charges affec

lara31 [8.8K]

Answer:

The force between the charges are not affected.

Explanation:

Given;

distance between two equal charges, R = 2m

The force between the charges is given by;

$F = \frac{kq^2}{R^2}\\\\F_1 = \frac{kq_1^2}{R_1^2}\\\\When\ the \ charges \ and \ the \ distance \ are \ divided \ by \ two \ (q_2 = \frac{q_1}{2}, \ R_2 = \frac{R_1}{2} )\\\\ F_2 = \frac{kq_2^2}{R_2^2}\\\\F_2 = \frac{k(q_1/2)^2}{(R_1/2)^2}\\\\F_2= \frac{4k*q_1^2}{4*R_1^2}\\\\F_2 = \frac{k*q_1^2}{R_1^2}\\\\F_2 = F_1$

Therefore, the force between the charges are not affected.

7 0

2 years ago

What is the time period of vibration?

Y_Kistochka [10]

Answer:

A time period is denoted by 'T' . It is the time to complete one cycle of vibration. As the frequency of a wave increases, the time period of the wave decreases. The unit for time period is 'seconds

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

4 0

2 years ago