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3 years ago

You can find the pH of a substance by using

Chemistry

1 answer:

soldier1979 [14.2K]3 years ago

8 0

The correct answer is C. Litmus Indicator

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4. A gas has a temperature of 14 degrees C and volume of 4.5 liters. If the temperature is raised to

nlexa [21]

Answer:

v2=4.735L

Explanation:

using charles law

v1\t1 = v2\t2

v1= 4.5L

t1= 14+273= 287K ( temperature has to be in kelvins)

t2=29+273= 302K

v2=?

by substitution;

4.5\287 = v2\302

v2=(302 x 4.5)\287

v2=4.735L

7 0

3 years ago

:))) hvjhvjhvkvjhvjhvjhvhv

Lapatulllka [165]

Wjndbdjskskshdbdbi :)))

3 0

4 years ago

What era is know as the age of mammals?

kondaur [170]

The era that is know as the age of mammals is the Mesozoic period.

Answer: Letter D

Hope that helps. -UF aka Nadoa

7 0

4 years ago

Suppose two 200.0-L tanks are to be filled separately with the gases helium and hydrogen. What mass of each gas is needed to pro

Aneli [31]

Answer:

Mass of helium = 4426.9524 g

Mass of hydrogen gas = 2213.4762 g

Explanation:

Pressure = 135 atm

Temperature = 24 °C

Volume = 200 L

Number of moles = ?

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (24 + 273.15) K = 297.15 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

135 atm × 200 L = n × 0.0821 L.atm/K.mol × 297.15 K

⇒n = 1106.7381 moles

For helium gas:

Molar mass = 4 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$1106.7381= \frac{Mass}{4}$

$Mass= 4426.9524\ g$

For hydrogen gas:

Molar mass = 2 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$1106.7381= \frac{Mass}{2}$

$Mass= 2213.4762\ g$

4 0

4 years ago

A mixture of methane and carbon dioxide gases contains methane at a partial pressure of 431 mm Hg and carbon dioxide at a

KatRina [158]

Answer:

XCH₄ = 0.461

XCO₂ = 0.539

Explanation:

Step 1: Given data

Partial pressure of methane (pCH₄): 431 mmHg

Partial pressure of carbon dioxide (pCO₂): 504 mmHg

Step 2: Calculate the total pressure in the container

We will sum both partial pressures.

P = pCH₄ + pCO₂

P = 431 mmHg + 504 mmHg = 935 mmHg

Step 3: Calculate the mole fraction of each gas

We will use the following expression.

Xi = pi / P

XCH₄ = pCH₄/P = 431 mmHg/935 mmHg = 0.461

XCO₂ = pCO₂/P = 504 mmHg/935 mmHg = 0.539

3 0

3 years ago