below left is a cylinder containing water. an ball with a mass of 21g and a volume of 15 cm3 is lowered into the water. sketch t
he object and the new water level in the cylinder on the right.
1 answer:
You didn’t show the cylinder containing water, so I created one that you can use as a model (see image).
The water level was originally at 37 mL.
Then you added the ball, and it displaced its volume of water.
The new volume reading is 52 mL, so
Volume of ball = volume of displaced water = 52 mL – 37 mL = 15 mL.
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Answer:
3.5 × 10⁵ g of salt
Explanation:
<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>
We have this data:
- 1.000 mol salt is equal to 58.44 g salt
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We will need the following relations:
- 1 L = 1dm³
- 1 m³ = 10³ dm³
We can use proportions: