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3 years ago

OMG PLEASE HELP. WILL MARK U BRAINLIEST IF YOU ANSWER ALL 3 QUESTIONS. THANKS SO MUCH.

Chemistry

1 answer:

Readme [11.4K]3 years ago

4 0

1.) Moe will feel pain and he will see one side go to the right and disappear

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c) If 21.0 g of potassium reacts with 62.5 g of barium nitride, what mass of potassium nitride will be produced?

MAXImum [283]

Explanation:

21.0 g of potassium reacts with 62.5 g of barium nitride, what mass of potassium nitride will be produced

8 0

3 years ago

A liquid occupies 321ml and has a mass of 376g. what is the density of the liquid?

oee [108]

Answer:

The density of the liquid is 1.153 grams/ml.

Explanation:

You have to use the fomula of density

density = mass/volume ⇒ density = 376 grams/321 ml ⇒

density = 1.153 grams/ml.

6 0

3 years ago

The ph of a fruit juice is 3.2. find the hydronium ion concentration, left bracket upper h 3 upper o superscript plus right bra

melomori [17]

pH is referred to as the scale to describe the hydronium ion concentration of a

solution. It is used to measure the acidity or basicity of a solution. pH of an acidic solution is less than 7, a neutral solution is 7, and a basic solution is greater than 7.

pH can be calculated using the formula:

$pH = - log [H_{3}O^{+}]$

Given the pH of solution is 3.2.

Finding out the concentration of hydronium ion from pH.

$pH = - log[H_{3}O^{+}]$

$3.2 = - log [H_{3}O^{+}]$

$[H_{3}O^{+}] = 10^{-3.2}$

$[H_{3}O^{+}] = 6.3 * 10^{-4} M$

Therefore, the hydronium ion concetration of the solution is $6.3 * 10^{-4} M$

3 0

3 years ago

24 how many moles are in 2.04 × 1024 molecules of h2o?

Sergeeva-Olga [200]

The answer is 3.39 mol.

Avogadro's number is the number of molecules in 1 mol of substance.
6.02 × 10²³ molecules per 1 mol.
2.04 × 10²⁴ molecules per x.

6.02 × 10²³ molecules : 1 mol = 2.04 × 10²⁴ molecules : x
x = 2.04 × 10²⁴ molecules * 1 mol : 6.02 × 10²³ molecules
x = 2.04/ 6.02 × 10²⁴⁻²³ mol
x = 0.339 × 10 mol
x = 3.39 mol

8 0

3 years ago

A student weighed out a 2.055 g sample of a cobalt chloride hydrate, ConClmpH2O, where n, m, and p are integer values to be dete

topjm [15]

The given mass of cobalt chloride hydrate = 2.055 g

A sample of cobalt chloride hydrate was heated to drive off waters of hydration and the anhydrate was weighed.

The mass of anhydrous cobalt chloride = 1.121 g anhydrate.

The mass of water lost during heating = 2.055 g - 1.121 g = 0.934 g

Converting mass of water of hydration present in the hydrate to moles using molar mass:

Mass of water = 0.934 g

Molar mass of water = 18.0 g/mol

Moles of water = $0.934 g * \frac{1 molH_{2}O }{18 g H_{2}O } =0.0519 mol H_{2}O$

8 0

3 years ago