Answer:
The displacement is 6.71 [m} and the angle is 63.4° to the north of east
Explanation:
Using a sketch showing Dante's displacement, we can find each of the points Dante moves through. First, it moves 4 blocks east, the new coordinate (4.0), then moves 3 blocks south and we will get the new coordinate (4, -3). Then Dante moves 1 block west, thus the new point is (3, -3). And finally it moves 9 blocks north where the new coordinate in and gets -3 - (-9) = + 6.
The displacement can be found using the equation for the straight line.
![d= \sqrt{(x_{1}-x_{0} )^{2} +(y_{1}-y_{0} )^{2} } \\d= \sqrt{(3-0 )^{2} +(6-0 )^{2} } \\\\d=6.71 [m]\\](https://tex.z-dn.net/?f=d%3D%20%5Csqrt%7B%28x_%7B1%7D-x_%7B0%7D%20%29%5E%7B2%7D%20%2B%28y_%7B1%7D-y_%7B0%7D%20%29%5E%7B2%7D%20%7D%20%5C%5Cd%3D%20%5Csqrt%7B%283-0%20%29%5E%7B2%7D%20%2B%286-0%20%29%5E%7B2%7D%20%7D%20%5C%5C%5C%5Cd%3D6.71%20%5Bm%5D%5C%5C)
We can realize that the triangle formed is a right triangle, therefore we can find the angle of the displacement.
![tan(a)=\frac{6}{3} \\a=tan^-1(2)\\a=63.4[deg]](https://tex.z-dn.net/?f=tan%28a%29%3D%5Cfrac%7B6%7D%7B3%7D%20%5C%5Ca%3Dtan%5E-1%282%29%5C%5Ca%3D63.4%5Bdeg%5D)
Answer:
E = h f and since f = c / λ we have E = h c / λ
Thus λ = h c / E
Also, 1 ev = 1.6E-19 C
λ = 6.63E-34 * 3.0E8 / (1.6 * 1.6E-19)
λ = 6.63 * 3.0 / (1.6 * 1.6) * E-7
λ = 7.77E-7 = 777 nanometers
(B) is correct
Answer:
A measuring cylinder contains 30 cm :))
Explanation: Hope this helps !!!!
Answer:
(3) mass-energy must be conserved
Explanation:
As we know that gamma rays are mass less and charge less photons which will have sufficient energy.
Now in case of Pair production the gamma photons convert its whole energy into mass by the law of Einstein's mass energy equivalence relation.
As per his relation we can say
here we will have
[tex]\Delta m[\tex] = mass produced
now we also have to think that here the two particles must have a pair of particles and antiparticles so that the combined mass system will have energy equivalent to the energy of gamma photons and also it must follow the conservation of charge
So here it will form an electron and a positron such that total charge will be zero and the energy will be same as energy of gamma photon.
